Register to reply

Critical angle and area

by mogley76
Tags: area, critical angle, optics water
Share this thread:
mogley76
#1
Aug24-11, 08:29 PM
P: 19
1. The problem statement, all variables and given/known data
calculate the critical angle for light at a water (n=1.33) and air (n=1) interface.
if a fish is 2m below the surface of the water , calculate the area at the surface through which the fish can viw the world above the water.

2. Relevant equations

none given

3. The attempt at a solution

critical angle = sin theta c= n2/n1 = 48.75 deg

area of surface=

using basic trig find out all the sides and angles of triangle ..
then area of tribgle is .5*2.28*2 = 2.28 m^2

am i right in all this??
Phys.Org News Partner Science news on Phys.org
Pilot sites in energy from coffee waste show good results
Startups offer banking for smartphone users
Factor in naked mole rat's cells enhances protein integrity
lightgrav
#2
Aug24-11, 08:47 PM
HW Helper
lightgrav's Avatar
P: 1,117
the Area on the SURFACE that the fish sees thru ...
it looks like a circular disk of bright blue sky directly above the fish ... out to 48deg.


Register to reply

Related Discussions
Critical angle = brewster angle? Advanced Physics Homework 5
Snell's law, critical angle, and angle of incidence Introductory Physics Homework 6
Critical angle Introductory Physics Homework 2
Critical angle/ last angle of refraction Introductory Physics Homework 6
Critical angle... General Physics 1