What Distance is Required to Stop a Car Moving at 50 m/s?

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Homework Help Overview

The discussion revolves around determining the stopping distance of a car moving at 50 m/s, given a known stopping distance for a lower speed. The subject area includes concepts of kinematics and motion under uniform acceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to establish a ratio between stopping distance and velocity, expressing confusion about the correctness of this approach. Another participant provides a calculation method using kinematic equations to find the stopping distance for the higher speed. There is a question about whether this is the only method available for solving the problem.

Discussion Status

The discussion includes various approaches to the problem, with one participant providing a calculation and another seeking alternative methods. There is no explicit consensus on the best approach, but a calculation has been shared that offers a potential solution.

Contextual Notes

The original poster expresses uncertainty about their method and seeks clarification on the reasoning behind the calculations. There may be assumptions regarding the conditions under which the car stops that are not fully explored.

Soaring Crane
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If it takes 50 m to stop a car initially moving at 25 m/s, what distance is required to stop a car moving at 50 m/s under the same condition?

a. 50 m
b. 100 m
c. 200 m
d. 400 m

This is probably a really easy question, but I just can't see how to work it out. I tried to set up a ratio between the distance and velocity and that got me 100 m, but b is incorrect. Can anyone explain the correct method to do this problem and tell me why setting up a ratio between those 2 components is a mistake?
 
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Answer is C

Vf^2=Vi^2+2ad
0=25^2+2(a)50
a=-6.25m/s^2

now you know the deceleration of the car

Vf^2=Vi^2+2ad
0=50^2+2(6.25)d
d=200m
 
Thanks. Is this the only way you can solve it?
 
This is the way I would solve it. Hope others give some posts
 

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