What Mistakes Did I Make in Solving This Circuit Problem?

  • Thread starter Thread starter needhelpperson
  • Start date Start date
  • Tags Tags
    Circuit
Click For Summary
SUMMARY

The discussion focuses on solving a circuit problem using Kirchhoff's laws and Ohm's law. The user initially assumed Vbc = Vdc, which led to incorrect results. Key steps to correctly analyze the circuit include drawing the circuit diagram, applying Kirchhoff's voltage and current laws, and using Ohm's law to calculate voltage drops. The correct approach involves creating a system of equations to solve for unknown voltages and currents, ensuring all calculations align with the laws of circuit analysis.

PREREQUISITES
  • Understanding Kirchhoff's Voltage Law (KVL)
  • Understanding Kirchhoff's Current Law (KCL)
  • Proficiency in Ohm's Law (V=IR)
  • Ability to create and solve systems of equations
NEXT STEPS
  • Learn how to draw and label circuit diagrams effectively
  • Study advanced applications of Kirchhoff's laws in complex circuits
  • Explore techniques for solving systems of equations in electrical engineering
  • Review common mistakes in circuit analysis and how to avoid them
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to improve their skills in circuit analysis and problem-solving.

needhelpperson
Messages
110
Reaction score
0
How do i solve this? I wasn't given any examples at all. But I've tried to do this.

Iab + Iad = Ibc + Idc <--------- they have to or else Kirchoff's law violated.

so Vab = Vad but I'm not sure if Vbc = Vdc?
i'll continue assuming Vbc = Vdc

Vab/40 + Vad/20 = Vbc/70 + Vdc/50

Va=0.45714286 Vc

Vbd/60+ Vc/50 = Va/20

Vbd = 0.1714286Vc

i thought that Va + Vc + Vbd = 20

solved for Vc and i got Vbd as 2.105263 V

The answer is 0.94V. Obviously i got something wrong here. Can some one explain to me where I went wrong, and how i can fix this. Thanks
 

Attachments

  • problem.jpg
    problem.jpg
    10.4 KB · Views: 537
Physics news on Phys.org
needhelpperson said:
so Vab = Vad but I'm not sure if Vbc = Vdc?
i'll continue assuming Vbc = Vdc
Your problem is you continue to asume that Vbc=Vdc, that lead you to the wrong answer.
First, you should find the current for the whole circuits, you can divide the circuits into parts .Then you can find the pottential of each part, then you can find the current of each resistance, then you subtract them to find the dirrection of the current through Rbd. Be careful at the last part.
 


It seems like you have correctly applied Kirchoff's law to the circuit, but there may be some issues with your calculations. Here are some steps you can follow to solve the circuit problem:

1. Start by drawing the circuit diagram and labeling all the known values, such as the resistors and voltage sources.

2. Apply Kirchoff's voltage law to each closed loop in the circuit. This means that the sum of all voltage drops in a closed loop must equal the sum of all voltage sources in that loop.

3. Apply Kirchoff's current law at each junction in the circuit. This means that the sum of all currents entering a junction must equal the sum of all currents leaving that junction.

4. Use Ohm's law (V=IR) to calculate the voltage drops across each resistor.

5. Use the equations from steps 2 and 3 to create a system of equations. This will help you solve for the unknown voltages and currents in the circuit.

6. Solve the system of equations to find the values of Vab, Vad, Vbc, Vdc, and Vbd.

7. Double-check your calculations and make sure they are consistent with the given values and Kirchoff's laws.

If you are still having trouble, it may be helpful to consult with a classmate or your instructor for clarification. It's also important to carefully check your calculations and make sure you are using the correct units. Good luck with your circuit problem!
 

Similar threads

Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
20K
Replies
10
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
1
Views
6K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 3 ·
Replies
3
Views
11K
Replies
2
Views
4K