Solve f(x) = (ax+b)/(x-c): Determine a,b,c

[needhelpperson]

f(x) = (ax+b)/(x-c) has the following properties

i) the graph of f is symmetric with respect to the y-axis
ii) lim x->2^+ f(x) = + infinite
iii) f^prime (1) = -2

a) Determine the values of a, b and c.

i think c = 2

derivative of f(x) = (-ca - b)/(x-c)^2

so f^prime(1) = -2

-ca-b = (1-c)^2 * -2

if c = 2 then b = -2a + 2

I'm stuck from here. I have no idea how to do this. I tried using this equation
(ax+b)/(x-2) = (-ax + b)/(-x-2)

since symmetric over y-axis and i plugged in b, but it turned out to be useless. Please help. thanks

 

[learningphysics]

Check the question again, and the 3 conditions. As the question is stated, I don't think there's any solution for a,b and c.

 

[James R]

I agree. There seems to be no solution.

 

[needhelpperson]

thanks for your time. This was all my teacher's fault. He didn't give us the correct question. It was (ax+b)/(x^2-c). Wow what a waste of time. I solved it anyways though, and again thanks for all your time.