How Do You Calculate Final Velocity and Change in Momentum for a Moving Body?

Click For Summary

Homework Help Overview

The discussion revolves around calculating final velocity and change in momentum for a moving body, specifically applying Newton's second law in the context of a body subjected to an external force. The subject area includes dynamics and momentum in physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing the calculation of final velocity and change in momentum for a body acted upon by a force. There are attempts to clarify the application of Newton's second law and the effects of directional changes in velocity. Some participants express confusion regarding their calculations and seek assistance in identifying errors.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning the discrepancies between their results and those provided by their instructor. Some guidance has been offered regarding the importance of considering the direction of velocities, but no consensus has been reached on the correct approach or solution.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the type of assistance they can receive. There is an emphasis on understanding the problem rather than receiving direct answers.

phyzacs
Messages
12
Reaction score
0
hi guys I am a college junior...taking physics for the first time in my life...its fun...but still tuff...just can i get help with these couple questions..i mean it would be very gracious of any of u to help me out...i know I am new and all, but this place...i was just browsing around and it rocked sooo...and

wow i never new this place existed...i might come here much more often


question 1: a 3.0 kg body is initially moving northward at 15m/s. Then a force of 15N, towards the east acts on it for 4.0 s (a) At the end of the 4.0 s, what's the body's final velocity? (b) what is the change in momentum during the 4.0 s?


i know the answers...can you just show me how to work out part A? i got 60 for part B, and keep getting 25 for part A, but that's not it...

i would really appreciate this...thank you...illpost the other 3 questions as well ?
 
Physics news on Phys.org
The position of three particles written as (x,y) coordinates are, particle 1 (mass 4.0 kg) at (4.0m, 0m); particle 2 (mass 6.0kg) at (2.0m, 4.0m); particle 3 (mass 3.0 kg) at (-1.0m, -2.0) what is the location of the center of mass?


this one too pleasE?? how do you do it...i have answers...
 
A projectile of mass 2.0 Kg approaches a stationary target body at 8.0 m/s. The projectile is deflected through an angle of 90.0 degrees and its speed after the collision is 6.0 m/s. WHat is the speed of the target body after the collision is perfectly elastic?


any help on how to do this one guyzz??
 
phyzacs said:
The position of three particles written as (x,y) coordinates are, particle 1 (mass 4.0 kg) at (4.0m, 0m); particle 2 (mass 6.0kg) at (2.0m, 4.0m); particle 3 (mass 3.0 kg) at (-1.0m, -2.0) what is the location of the center of mass?


this one too pleasE?? how do you do it...i have answers...


ok i solved this one, so don't need it thanks...
 
phyzacs said:
question 1: a 3.0 kg body is initially moving northward at 15m/s. Then a force of 15N, towards the east acts on it for 4.0 s (a) At the end of the 4.0 s, what's the body's final velocity?
Considering this is propably one of the easiest exercise you can make of Newton's second law and constant acceleration, you should really try solving it again. Keywords: Newton's second law and motion with constant acceleration ;)
 
brother i am doing it,...the answer i am getting is 35...teacher says it is 25...what am i doing wrong inthe calculations?
 
Perhaps, if you showed us your solution, we could help find the error.

Also, we have a homework help forum, just for this type of post.
 
phyzacs said:
brother i am doing it,...the answer i am getting is 35...teacher says it is 25...what am i doing wrong inthe calculations?
My guess is you are forgetting that the directions of the two velocities are different (first 15m/s to north and second caused by the force is to east).
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
10
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K