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diagonal bases in transformations |
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| Sep7-11, 03:52 AM | #1 |
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diagonal bases in transformations
1. The problem statement, all variables and given/known data
Let T: R3 - R3 be the linear operator given by T = -y + z -x + z x + y Find a basis B' for R3 relative to which the matrix for T is diagonal using the standard basis B for R3. 2. Relevant equations [T]B' = P-1[T]BP 3. The attempt at a solution I find the standard matrix for T to be 0 -1 1 -1 0 1 1 1 0 The characteristic equation of which, I find to be (lambda)^3 -3(lambda) + 2 = 0 Which has no real solutions? What can I do? Thanks Derryck |
| Sep7-11, 04:09 AM | #2 |
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well the matrix is symmetric so that should ensure real eigenvalues...
from visual inspection it appears 1 is a root |
| Sep7-11, 04:12 AM | #3 |
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Hi Derryck!
![]() (have a lambda: λ and try using the X2 icon just above the Reply box ) … how can a cubic equation have no real solutions? |
| Sep7-11, 04:18 AM | #4 |
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diagonal bases in transformations
I also got the same characteristic equation as well...
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| Sep7-11, 05:44 AM | #5 |
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Ok thanks guys. See the thing is I just put it into excel to help me find roots. I must have entered the wrong formula though:( It came up with an irrational number? Anyway...I can definitely see that 1 is a root now...thanks...
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