One dimensional motion of a tortoise

Click For Summary

Discussion Overview

The discussion revolves around a problem involving one-dimensional motion, specifically comparing the speeds and distances covered by a tortoise and a hare in a race. Participants explore the implications of the tortoise winning by a specific distance while the hare takes a break.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents the speeds of the tortoise and hare, suggesting that the tortoise runs at 0.10 m/s and the hare at 2.0 m/s.
  • Another participant formulates the distances covered by both animals in terms of time, proposing equations based on their speeds and the hare's resting time.
  • A third participant clarifies the relationship between the distances covered and the condition that the tortoise wins by 20 cm, leading to a specific equation that needs to be solved.

Areas of Agreement / Disagreement

Participants generally agree on the formulation of the problem and the equations needed to solve it, but no consensus is reached on the final solution or the specific values for the race duration and length.

Contextual Notes

The discussion relies on the assumption that the speeds and resting times are accurately represented, but does not address potential limitations in the problem's setup or the need for further clarification on the conditions of the race.

Who May Find This Useful

Students or individuals interested in physics problems related to motion, particularly those involving comparative speed and distance calculations.

Physicstudent
can anyone help me with this problem please--

A tortoise can run with a speed of 0.10 m/s and a hare can run 20 times as fast. in a race they both start at the same time but the hare stops to rest for 2.0 minutes. the tortoise wins by 20 cm.

how long does the race take?
what is the length of hte race?
 
Physics news on Phys.org
I guess the totoise runs 0.10*t and the hare 20*0.10*(t-120) meters. One little first degree equation...
 
The distance the tortoise covers in t seconds is 0.10*t meters and the distance the hare covers is 20*0.10*(t-120) meters as Sonty said. However, the condition that "the tortoise wins by 20 cm" means that, if t is the time when the tortoise crosses the finish line, then 20*0.10*(t-120)= 0.10*t- 0.2. That's the equation you need to solve.
 
thank u both
 

Similar threads

Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 27 ·
Replies
27
Views
3K
Replies
1
Views
5K
  • · Replies 36 ·
2
Replies
36
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K