One skater pushes another skater

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SUMMARY

The discussion focuses on determining the masses of two skaters who together weigh 120 kg and push off from each other, achieving speeds of 3.3 m/s and 2.1 m/s. The principle of conservation of momentum is applied, stating that the initial momentum is zero, leading to the equation m1 * v1 + m2 * v2 = 0. By substituting the known values and solving the resulting equations, the individual masses can be calculated using the relationship between mass, velocity, and momentum.

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I need to determine the masses of two skaters, who together weigh 120kg. They stand still opposite each other. Then they push each other away from away from each other. One of them gain the speed of 3,3m/s and the other one 2,1m/s.
How do you determine their masses?
I know it has something to do with impulses, but I can't figure it out...
 
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This is a conservation of momtum proplem. Before the skaters push off their momentum is zero, so it must be after the push off. Can you take it from there?
 
[tex]\vec{p}=m\vec{v}[/tex]
where p is momentum. As Integral said,
[tex]\vec{p}_{initial}=\vec{p}_{final}[/tex]
You know initial momentum is zero, so find an expression for the final momentum and set it equal to zero.
 

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