Moment of Inertia and Kinetic Energy of Rotating Disk with Block

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Homework Help Overview

The discussion revolves around calculating the moment of inertia and kinetic energy of a rotating disk with a block attached to its rim. The problem involves concepts from rotational dynamics, specifically focusing on the moment of inertia and angular motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of the moment of inertia for both the block and the disk, questioning the correct distances to the rotation axis. There is also discussion about the kinetic energy of the system and the acceleration of the block.

Discussion Status

Some participants have offered guidance on the correct distances to use in calculations, while others are clarifying their understanding of the formulas involved. There is ongoing exploration of the correct values to apply in the kinetic energy calculation.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can use or the methods they can apply. There is some confusion regarding the distances from the block to the rotation axis, which affects the calculations being discussed.

Naeem
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A uniform disk of mass Mdisk = 4.4 kg and radius R = 0.28 m has a small block of mass mblock = 2.4 kg on its rim. It rotates about an axis a distance d = 0.18 m from its center intersecting the disk along the radius on which the block is situated.


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a) What is the moment of inertia of the block about the rotation axis?
Iblock = kg*m2
2*0.18*0.18 NO

HELP: Remember: the block is on the rim of the disk.
HELP: The block is considered a point-mass.


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b) What is the moment of inertia of the disk about the rotation axis?
Idisk = kg*m2 *
4.4*0.28^2/2+4.4*0.18^2 OK


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c) When the system is rotating about the axis with an angular velocity of 5 rad/s, what is its energy?
KErot = J
(2.4*0.18^2+4.4*0.28^2/2+4.4*0.18^2)*5.0^2/2 NO


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d) If while the system is rotating with angular velocity 5 rad/s it has an angular acceleration of 8.4 rad/s2, what is the magnitude of the acceleration of the block?
|ablock| = m/s2
((5^2*0.18)^2+(8.4*0.18)^2)^(1/2) NO

Somebody please help!
 
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a)
i) What is the mass of the block?
ii) What is the distance of the block to the rotation axis?
c)"(2.4*0.18^2+4.4*0.28^2/2+4.4*0.18^2)*5.0^2/2 NO"
Use the correct answer to aii)!
 
OK, for a, here is what I did:
I = MR square
so,

I = Mblock * distance square
= 2.4 * 0.18 * 0.18 , but still the answer is wrong!
 
But the distance from the BLOCK to the rotation axis is 0.28-0.18=0.10
 
OK, got that one can u help on c & d. Some inital guidance.
 
For c), you've used the wrong distance for the block.
On d) you should use:
[tex]||a||=\sqrt{r^{2}(\dot{\omega})^{2}+(r\omega^{2})^{2}}[/tex]
where [tex]\omega[/tex] is the angulur velocity, [tex]\dot{\omega}[/tex] the angular acceleration, and r the radius to the rotation axis.

Note that this is just the formula you've been using but with the wrong radius value..
 
Last edited:
I got part d, need help with part c , then is the correct distance 0.10 m, if so,
is this correct:

2.4*0.10^2+4.4*0.28^2/2+4.4*0.10^2)*5.0^2/2
 
"2.4*0.10^2+4.4*0.28^2/2+4.4*0.10^2)*5.0^2/2"

"4.4*0.10^2"
Why did you change this value??
It should be, as it was initially 4.4*0.18^2
 
The correct should be as follows: (2.4*0.10^2+4.4*0.28^2/2+4.4*0.18^2)*5.0^2/2

I got , this and all, thank you.!
 

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