Calculate Heat of Formation for SO3 Gas using Hess' Law - Step by Step Guide"

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Homework Help Overview

The discussion revolves around calculating the heat of formation for one mole of SO3 gas using Hess' Law, based on provided reaction data involving sulfur and oxygen compounds.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to derive the correct reaction equation for the formation of SO3 gas from the given data. There is an exploration of how to manipulate the provided equations to arrive at the desired formation reaction.

Discussion Status

Some participants have offered guidance on how to approach the problem by suggesting the addition and manipulation of the given equations. There is an ongoing evaluation of the steps taken to ensure the calculations align with Hess' Law.

Contextual Notes

Participants express uncertainty about the initial steps and the proper handling of the equations, indicating a need for clarification on the formation process and the calculations involved.

GodsChild086
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Compute the heat for formation of one mole of SO3 gas from the following data:

Sorry I don't know how to do subscripts...

S8(s) + 8O2(g) --> 8SO2(g) + 2378.4 kJ
SO2(g) + 1/2O2(g) --> SO3(g) + 99.0 kJ

I don't have a clue where to start...
 
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Since you are finding out the heat for formation of one mole of SO3 gas, it is necessary for you to find out the reaction equation for the foramation of SO3 gas using the given data first. By addition/subtraction/multiplication/division the given data, you can find out the equation, and therefore find out the heat for formation.
 
So is this right?

I'm going to multiply the second equation by 8...

S8(s) + 8O2(g) --> 8SO2(g) + 2378.4 kJ
8SO2(g) + 4O2(g) --> 8SO3(g) + 792 kJ

Balanced equation (well adding the both of them together):

S8(s) + 12O2(g) --> 8SO3(g)

________________________________________________________________
-2378.4 kJ + (-792 kJ) = -3170.4 kJ

-3170.4 kJ/8 mol x 1 mol = -396. 3 kJ[/color] (the mol's will cancel)
 
Um, Yes. I think it is right!
 

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