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Resistor Heat Dissipation (with imaginary numbers)

 
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Nov29-11, 09:55 PM   #1
 

Resistor Heat Dissipation (with imaginary numbers)


Friends:

I am wondering about heat dissipation when you have imaginary numbers.

Lets say a current I = (3 + 4j) Amps is going through an impedance Z = (2 + 3j) Ohms. What is the amount of heat dissipated by the impedance?

I think that you take the magnitude of the current, |I| = 5 Amps, and then find the heat dissipated by only the real part of the impedance, Re(Z) = 2. The heat dissipated would be P = (5^2)*2 = 50 W.

Is this correct?

Note: This is not a homework question. This is something I just wanted to verify.
 
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Nov30-11, 12:05 AM   #2
 
Recognitions:
Homework Helper Homework Help
The RMS power is:
[tex]P_{RMS}={|I|^2 \over 2} |Z|[/tex]
 
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dissipation, heat, imaginary, impedance, resistance
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