Register to reply

Simple harmonic motion question please help!

by Eats Dirt
Tags: harmonic, motion, simple
Share this thread:
Eats Dirt
Nov29-11, 10:48 PM
P: 70
1. The problem statement, all variables and given/known data

An object undergoing SHM with a period 0.9s and amplitude of 0.32 m at t=0 the object is at 0.32 m and is instantaneously at rest. Calculate the time it takes the object to go a) from 0.32 to 0.16 m
b) from 0.16 m to 0

i can do a but dont understand why when i do the calculation x is not -1/2 and is 1/2

2. Relevant equations

3. The attempt at a solution

so for first part 1/2 = 0.32 cos (2+2/9)*pi * t

i get 0.15 correct answer and for part b i do the same thing because it is the same distance excpt i shift the graph so t1 is at 0.16 like this 0.16 = a cos ((wt) - pi/4)
Phys.Org News Partner Science news on
Experts defend operational earthquake forecasting, counter critiques
EU urged to convert TV frequencies to mobile broadband
Sierra Nevada freshwater runoff could drop 26 percent by 2100
Nov30-11, 03:13 AM
P: 648
If 0.15s is the correct value for the time to reach 0.16m from 0.32m, then to reach 0 from 0.32m is the time for exactly one quarter of a period. (=0.9s/4)
The time from 0.16m to zero is then just the time for the quarter period minus your first answer.

Register to reply

Related Discussions
Simple Harmonic Motion Question. Introductory Physics Homework 6
A simple question on simple harmonic motion Introductory Physics Homework 14
Simple Harmonic Motion Question General Physics 7
Simple Harmonic Motion Question Introductory Physics Homework 1
Simple Harmonic Motion Question Introductory Physics Homework 3