Would this force be large enough to lift a 60 kg person?

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SUMMARY

The average force exerted on a tennis ball by a racket during a serve is calculated using the formula F_{ave} = ΔP/Δt, where ΔP is the change in momentum and Δt is the time of contact. Given a ball mass of 0.0600 kg and a final speed of 62.0 m/s over a contact time of 0.0200 s, the average force is determined to be 186 N. This force is insufficient to lift a 60 kg person, as the required force to lift such a mass is approximately 600 N. Therefore, the force generated by the racket is not large enough to lift a person.

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A tennis ball may leave the racket of a top player on the serve with a speed of 62.0 m/s. If the ball's mass is 0.0600 kg and it is in contact with the racket for 0.0200 s, what is the average force on the ball?

Would this force be large enough to lift a 60 kg person?
large enough or
not large enough

I got .0600x62=3.72

.0200/3.72=.00537

I don't think that is right because that seems way to small but I don't know what I am missing...if it is incorrec that is.
 
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W = mg so the force needed to lift a 60kg person will be ~ 600N.
a = 62/0.02 = 3100
F = ma = 0.06*3100 = 186

So it is not large enough.
 
The force on the ball equals the change of its momentum with respect to time.

[tex]F_{ave}=\frac{\Delta P}{\Delta t}[/tex]

You already calculated its momentum when it leaves the racket, if we assume the ball is stationary before it is hit you can get the average force from the above formula.
 

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