## Variation of Pressure with Depth

1. The problem statement, all variables and given/known data
By what factor is the total pressure greater at a depth of 850 m of sea water than at the surface where the pressure is one atmosphere? (water density = 1000 kg/m3, one atmosphere pressure = 1.01 x 105 Pascals (N/m2), g = 9.8 m/s2 )

2. Relevant equations
P=P(initial)+ρgh

3. The attempt at a solution
P=(1.01x10^5)+(1000kg/m^3*9.8m/s^2*850m)
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 Your calculation gives you the pressure at the depth of 850m. The question is worded....'by what factor is the total pressure greater at a depth of 850m..... I think this means you are expected to give your answer as a ratio??
 ok, well how would I do that? the possible answers to the question are a. 100, b. 83, c. 74, d. 19. That is where I am stuck.

## Variation of Pressure with Depth

using P = hρg I got the pressure due to the water to be 8.33 x 10^6 Pa
Atmospheric pressure is 1.01 x 10^5 Pa
Get the ratio ????