Rotation with constant acceleration

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SUMMARY

The discussion focuses on calculating the final rotational speed of a flywheel with a mass of 40 kg and a diameter of 75 cm, initially spinning at 500 rpm, after experiencing friction over 30 seconds. The wheel completes 200 revolutions during this time, indicating a deceleration due to friction. By applying the rotational kinematic equation, specifically x = x_0 + v_0t + 1/2at^2, users can determine the acceleration and subsequently the final speed of the flywheel.

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gunnar
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A flywheel has mass 40 kg and diameter 75 cm is spinning at 500 rpm. During 30 sec the wheel slows down due to friction. The wheel makes 200 complete revolutions during the 30 sec.
At what rate is the wheel spinning at the end of the 30 sec?

Can somebody help with this problem please?
 
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Use the kinematic equations for uniform acceleration to solve for the acceleration, and then the final speed. For example, you can start with the rotational analog of this equation: [itex]x = x_0 + v_0t + 1/2at^2[/itex].
 
Thank's a lot. Really saved me there.
 

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