|Dec12-11, 05:04 PM||#1|
A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2 Determine the time for the feather to fall to the surface of the moon.
So, I wrote my given:
a= 1.67 m/s2
both initial and final velocity= 0
I know I am looking for time, but I have no idea what equation to use. I tried:
vf= vi+at , but I didn't get the right answer. The answer should be 1.29 s.
Any help would be much appreciated, please and thank you!:)
|Dec12-11, 05:07 PM||#2|
Well what equation involves d,a,t and u (initial velocity)?
|Dec12-11, 05:13 PM||#3|
This does: d=vi+1/2*at2
but I didn't get the right answer with that either, I got .75:(
|Dec12-11, 06:01 PM||#4|
I got the right answer now.:)
|acceleration, gravity, time|
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