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Power Factor OCT of Transformer |
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| Dec18-11, 06:57 PM | #1 |
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Power Factor OCT of Transformer
1. The problem statement, all variables and given/known data
See statement below. 2. Relevant equations 3. The attempt at a solution I've been reading through the notes for my course and in the section where we are determining the parameters for transformers. For the OCT they give, 240V, 1.066A, 136.6W From this they calculate Rc and Xm which I understand how to do but underneath in bold it says, "Calculate the power factor of the transformer during the OCT and comment." Wouldn't the PF of the transformer just be, [tex]PF = \frac{136.6W}{240V \cdot 1.066A} = 0.533[/tex] Is there something to take away from this? It wouldn't be put in bold in my notes for no reason. What am I to conlcude from this? |
| Dec18-11, 09:02 PM | #2 |
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Recognitions:
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I suppose the ideal OC pf would be 0. That would mean zero real power losses when the device is connected to the mains but completely unloaded. |
| Dec19-11, 12:21 AM | #3 |
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| Dec19-11, 07:14 PM | #4 |
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Recognitions:
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Power Factor OCT of Transformer
open circuit test
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| Dec19-11, 08:14 PM | #5 |
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Maybe your instructor likes bold type ... ? |
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