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Can we change Euler's Formula? |
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| Dec19-11, 02:45 PM | #1 |
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Can we change Euler's Formula?
Is there a way to take Euler's formula "e^(i∅)" -which gives a circle; and change it into a logarithmic spiral?
Does a simple modification like " e^-(i∅/n) " make any sense mathematically? If it actually does, my other question would be; supposing that such a logarithmic spiral is in fact just a head on view of a space curve with parameters like: y=tsint x=tcost z=e^(-t/12) how does one go about finding the arc length of such a curve? I've attempted to use the general arc length formula on this one, but continually end up with something like: s = ∫ √e^-t/12 + t^2 + 1 which is, apparently, impossible to solve. Is there a way to use the complex variable in a formula like Euler's formula to create a logarithmic spiral? And if so, how does one go about calculating the arc length of such a thing? |
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| Dec20-11, 06:15 AM | #2 |
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Yeah - you change the amplitude with angle.
remember - euler's formula is for a circle in the complex plane. the logarithmic spiral formula is for the real plane. to change it to complex - just multiply the y parameterization by the square-root of minus one. OR: you could just set Aexp(it) so that A=the radius of the spiral at angle t. note: exp(it/n) just changes the frequency of the rotation. |
| Dec20-11, 11:41 AM | #3 |
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Maybe something like:
(cos [itex]\theta[/itex] + i sin[itex]\theta[/itex])/w would translate into: [exp(i[itex]\theta[/itex])] / w where w is some decreasing function related to [itex]\theta[/itex]? I don't know. I've been stuck on this one for almost two years. Thanks for your help. |
| Dec20-11, 11:50 AM | #4 |
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Can we change Euler's Formula?
The Wikipedia entry for "Circular Polarization" has the "classical sinusoidal plane wave solution of the electromagnetic wave equation" - and the math behind it as well.
It's similar, in general, to what I'm looking for. The math is beyond me. I actually know what some of those things are, but I think I would need to enroll in school again to understand usefully. Tough stuff. Maybe I should ask some physics guys how to transform Circular Polarization into Spiral Polarization. |
| Dec20-11, 02:53 PM | #5 |
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what if we take ei[itex]\Theta[/itex] and turn it into e-a+i[itex]\Theta[/itex]? Now we have a logrithmic spiral no?.
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| Dec20-11, 08:05 PM | #6 |
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Yes. That would seem to make sense. Correct me if I'm wrong reinterpreting the equation.
e-a + i[itex]\theta[/itex] = (e-a)(ei[itex]\theta[/itex])= (e-a)(cos[itex]\theta[/itex] + i sin[itex]\theta[/itex]) What kind of variable is "a" in this situation? Is this a three dimensional curve, or rather, can it be visualized in 3 dimensions? Thanks for your help there. |
| Dec20-11, 08:08 PM | #7 |
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I'm gonna have to suss that out for the arc length...hmm...getting closer.
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| Dec20-11, 09:35 PM | #8 |
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Taken as a locus of points in the complex plane, it is two dimensional. If a is a constant, then the locus is a circle. But you can also make the angle, any of them, a function of time - in which case, [itex]e^{i\theta(t)}[/itex] is rotating. You can make [itex]a[/itex] a function of time, or even of a third space dimension if you want ... and plot a locus in 3D or an evolving spiral path in 3+1. Consider: [tex]Ae^{\alpha t}e^{i\beta t} = Ae^{(\alpha+i\beta)t} = Ae^{zt}[/tex] if [itex]\alpha=\beta=1[/itex], what is the shape mapped out in the complex plane? You could also look at: [itex]at[\cos(bt)+i\sin(bt)][/itex], where a and b are arbitrary constants. Have fun. |
| Dec21-11, 04:04 PM | #9 |
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Replace [tex]i[/tex] in Euler's formula with [tex]i -1[/tex] and you get a logarithmic spiral:
[tex]e^{(i - 1)t}[/tex] parametrically describes a logarithmic spiral in the complex plane |
| Dec21-11, 06:35 PM | #10 |
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In other words, in OP notation, a=-t \theta = t.
But you can have fun experimenting with lots of different spirals besides the golden one :) |
| Dec21-11, 06:48 PM | #11 |
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| Dec21-11, 10:50 PM | #12 |
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"Logarithmic spiral"= r = a(exp)-b(theta) in polar coordinates
Parametric form: x(t) = r(t) \cos(t) = ae^{bt} \cos(t)\, y(t) = r(t) \sin(t) = ae^{bt} \sin(t)\, |
| Dec21-11, 10:53 PM | #13 |
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Are you wondering why I write the power in the exponent (theta) over "n"? Or what?
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| Dec21-11, 10:54 PM | #14 |
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Thanks again for all the replies. I will be pondering this one for a while.
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