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Percentage of Uncertainty 
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#1
Dec1004, 12:14 AM

P: 137

How do you go about finding the percentage in the uncertainty of momentum, if you already know the momentum and delta momentum? I'm asking because both of them end up being the same; thus I'm wondering if I'm terribly wrong. Any advice?



#2
Dec1004, 06:37 AM

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To find the percentage change divide the change in momentum by the (starting) momentum and multiply by 100%. The change in momentum has units of momentum but the percentage change has no units so they are not the same.



#3
Dec1004, 08:42 AM

P: 137

The thing which I've discovered is that when I use that formula, I only end up with 100% back again. Are delta p and p supposed to be the same? For I've taken the things I know, the uncertainty in position and charge, and rearranged them in order to solve for things which I don't know.



#4
Dec1004, 12:30 PM

P: 137

Percentage of Uncertainty
Any ideas guys?



#5
Dec1004, 12:31 PM

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#6
Dec1004, 02:13 PM

P: 137

It is about Heisenberg's Uncertainty Principle. We are given the uncertainty for the position of the 1 KeV electron, and we're asked to find the percentage of uncertainty in it's momentum. Now, I've already found the uncertainty of momentum. However, when I use that answer and solve for momentum, both mometum and the uncertainty in momentum are equal. Thus when I use the % formula: (delta p *100%)/p, I end up with 100% as my percentage. What am I doing wrong?



#7
Dec1004, 02:39 PM

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#8
Dec1004, 02:41 PM

P: 137

Doesn't that mean that my percentage in my uncertainty is 100%?



#9
Dec1004, 03:07 PM

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Daniel. 


#10
Dec1004, 03:10 PM

P: 137

the uncertainty of position is .100 nm



#11
Dec1004, 03:28 PM

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Daniel. 


#12
Dec1004, 03:36 PM

P: 137

The formula for KE = (p^2)/2m
k = 2pi/lambda, and delta p = h/lambda 


#13
Dec1004, 03:45 PM

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I also get less than 1% uncertainty.



#14
Dec1004, 03:53 PM

P: 137

with what formula



#15
Dec1004, 04:00 PM

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#16
Dec1004, 04:03 PM

P: 137

for delta p do you get 6.626 * 10^24?



#17
Dec1004, 04:06 PM

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#18
Dec1004, 04:22 PM

P: 137

I'm sorry to keep on testing your patience. So then we solve for k using k = 2pi/lambda, because lambda = delta x, and I get 6.283 * 10^10



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