How Do You Calculate Work Done by Gas in Thermodynamics?

[Enoch]

Thermodynamics problem: help needed!

Gas in a container expands at a constant pressure of 95 atmospheres. Find the work done by the gas if the initial volume is 5 L and the final volume is 10 L. Answer in units of Joules.

I thought this problem was straight-forward, but I missed it.

I converted 95 atmospheres into Pascals.

95 X 1.013e5 PA = 9623500

I then converted L into meters ^3.

Vi = 0.5 m^3
Vf = 1 m^3

With the units converted, I used the equation W = P(Vf - Vi) and got the answer 4811750 Joules. The answer is incorrect, or so I believe.

Where did I go wrong?

 

[dextercioby]

Gas in a container expands at a constant pressure of 95 atmospheres. Find the work done by the gas if the initial volume is 5 L and the final volume is 10 L. Answer in units of Joules.

I thought this problem was straight-forward, but I missed it.

I converted 95 atmospheres into Pascals.

95 X 1.013e5 PA = 9623500

I then converted L into meters ^3.

Vi = 0.5 m^3
Vf = 1 m^3

With the units converted, I used the equation W = P(Vf - Vi) and got the answer 4811750 Joules. The answer is incorrect, or so I believe.

Where did I go wrong?

There's no problem with the conversion of the pressure's units to SI,but remember that
$$1m^3=1000L$$

 

[Enoch]

There's no problem with the conversion of the pressure's units to SI,but remember that
$$1m^3=1000L$$

Thanks a lot!