What Is the Probability of Visiting a White and Even-Numbered House?

[ms. confused]

Need help with probability!

Can someone help me solve this problem?

Geri is going door-to-door in a neighbourhood where there are 14 blue houses, 18 white houses, and 22 houses with other colours. There are equal numbers of odd and even numbered houses of each colour. Geri is dropped off at random. What is the probability that the first house she visits will be white and even-numbered?

 

[quasar987]

Since there are as much even-numbered as there are odd-numbered, the probability that her first house be even-numbered is one out of two.

""Additionally"", there are 18 white houses out of 14+18+22 = 54 houses. So her chances of hitting a white house are of 18/54 = 1/3.

So the probability that she gets the two combined (white AND even-numbered) is therefor of (1/2)(1/3) = 1/6.

 

[wais]

To solve this problem, we first need to determine the total number of houses in the neighborhood. Since there are 14 blue houses, 18 white houses, and 22 houses with other colors, the total number of houses is 14 + 18 + 22 = 54.

Next, we need to determine the number of white and even-numbered houses in the neighborhood. Since there are equal numbers of odd and even numbered houses of each color, there are 18/2 = 9 white and even-numbered houses.

Therefore, the probability of Geri visiting a white and even-numbered house is 9/54 = 1/6 or approximately 0.167.

I hope this helps you with your probability problem! If you have any further questions, feel free to ask.