Problem with two review problems

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Homework Help Overview

The discussion revolves around two mathematical problems: one involving the perimeter of an isosceles triangle with given angles and area, and another concerning the dimensions of a rectangular workbench related to its length and width. Participants are exploring the geometric properties and relationships involved in these problems.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the understanding of the isosceles triangle's properties, particularly regarding the angles and area formula. There is also a request for clarification on the dimensions of the rectangular workbench and how the changes in width and length relate to forming a square.

Discussion Status

Some participants have offered guidance on starting points for the problems, including the area formula for the triangle. There is an ongoing exploration of the implications of the triangle's angles and the conditions for the rectangular workbench, with no explicit consensus reached yet.

Contextual Notes

Participants express uncertainty about the formulation of the triangle problem and the assumptions regarding the angles. There is a suggestion that the original problem may not align with typical geometric expectations, indicating a potential misunderstanding of the isosceles triangle's properties.

maverick99
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First of all, thanks for anyone who helps me with this

1. Find the perimeter of an Isoceles triangle that has base angles of 36 degrees and an area of 580cm sq.
The given answer is 126.4cm.

2. A designer plan the top of a rectangular workbench to be four times as long as it is wide, and then determines that if the width is 2.5 ft greater and the length is 4.7ft less, it wouldbe a square. What are its dimensions?
 
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maverick99 said:
First of all, thanks for anyone who helps me with this

1. Find the perimeter of an Isoceles triangle that has base angles of 36 degrees and an area of 580cm sq.
The given answer is 126.4cm.

2. A designer plan the top of a rectangular workbench to be four times as long as it is wide, and then determines that if the width is 2.5 ft greater and the length is 4.7ft less, it wouldbe a square. What are its dimensions?

1.& 2.What have you done so far?The problems are not difficult,and therefore it's better that u did them yourself,maybe with some help from us.Post your work.

Daniel.
 
dextercioby said:
1.& 2.What have you done so far?The problems are not difficult,and therefore it's better that u did them yourself,maybe with some help from us.Post your work.

Daniel.

I just need help starting both of them, that's all.
 
Well - what's the formula in getting the area of the triangle??
You should start off with that.
 
futb0l said:
Well - what's the formula in getting the area of the triangle??
You should start off with that.

well i know that its 1/2(b)(h) but i don't know what it means by 2 base angles of 36 degrees. Since it's isocoles, doesn't it have a right angle, therefore 36+36+90=162 which it should add up to 180
 
maverick99 said:
well i know that its 1/2(b)(h) but i don't know what it means by 2 base angles of 36 degrees. Since it's isocoles, doesn't it have a right angle, therefore 36+36+90=162 which it should add up to 180

I doubt the original problem was formulated with a triangle on a saddle (negative total curvature),but in a plane,so those angles should add up to 180°.
U'll find more useful this formula:
[tex]S_{triangle}=\frac{1}{2}l_{1}l_{2} \sin \alpha[/tex]
,where [itex]\alpha[/itex] is the angle between those 2 sides l_1 and l_2.

Daniel.
 
isosceles doesn't mean right angle it's just
36+36+ 108 = 180
 

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