Finding Uncertainty in $\theta$ with Fixed $\lambda$

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The discussion focuses on calculating the uncertainty in the angle \(\theta\) defined by the equation \(\theta = \sin^{-1}\left(\frac{n\lambda}{d}\right)\) with fixed \(\lambda\). The user initially miscalculated the uncertainty \(\delta \theta\) due to incorrect application of derivatives and assumptions regarding the variable \(n\). After clarification, it was established that if \(n=1\), the calculations should be revisited to ensure accuracy. The final resolution indicated that the user's previous calculations were flawed, leading to an incorrect uncertainty value.

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I'm trying to find the uncertainty in [tex]\theta[/tex] where [tex]\theta[/tex] is given by:

[tex]\theta=sin^{-1}\frac{n\lambda}{d}[/tex]

in this case, I am assuming there is no uncertainty in [tex]\lambda[/tex].

This is what I tried:

[tex]\delta \theta=\sqrt{(\frac{d\theta}{dd})^2(\delta d)^2}[/tex]

(the total derivative in there should be a partial derivative, but I don't know how to get that symbol)

[tex]\delta \theta=\sqrt{(\frac{\frac{\lambda}{d}}{\sqrt{d^2-\lambda^2}})^2\delta d^2}[/tex]

I think that is right, but if I use the values [tex]\lambda=632.8 nm, d=1.08 \mu m[/tex] and [tex]\delta d =.001 \mu m[/tex] I get an uncertainty of almost 450 degrees. Where am I making my mistake?
 
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1.Click on this:[tex]\partial[/tex].
2.U assumed "n=1",else that derivative should have included the product [itex]n\lambda[/itex].
3.If [itex]n\neq 1[/itex],then you should include "n" in the derivative (under the square root) and redo your calculations.
4.If "n=1",then it's either the numbers are badly chosed,or u ****ed those calculations.

Daniel.
 
1. Thanks for the latex lesson
2. n=1
3. Turns out it was just my math. Although I did that calculation at least 4 or 5 times and kept getting the same answer before. I don't know what I was doing wrong, but it works much better now.
 

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