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object sliding down horizontal, frictionless slope, crossing horizontal surface |
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| Jan16-12, 12:33 PM | #1 |
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object sliding down horizontal, frictionless slope, crossing horizontal surface
1. The problem statement, all variables and given/known data
block A slides down an 8 m frictionless ramp that is curved 30 degrees above the horizontal. it then crosses a 4m surface that has a coefficient of friction that is 0.20. it then hits a ball and continues moving at 3 m/s. the ball is suspended from a string, kinda like a pendulum. You have to find out how high the ball goes. mass of block a is 5kg mass of ball a is 2.5 kg 2. Relevant equations Ek = 0.5mv^2 Eg = mgh vf^2 = vi^2 + 2ad Ff= μFn p=mv 3. The attempt at a solution to find the speed of the block after sliding down the ramp, i simply used some the sin function to determine the vertical distance the block moved down the ramp and then used the formula E(gravity)= mgh to find out the energy it had at the top of the ramp. I then converted this energy to kinetic energy (formula E(kinetic) = 0.5mv^2) which it would have gained at the bottom of the ramp and found the speed to be around 8.85 m/s. then to find the speed after the block crossed the 4m distance, i used the the formula for friction. To find the normal force, i used Fg = mg cuz gravity and normal force are the same in magnitude, and put this in the F(friction) = μFn formula and then got the negative acceleration and plugged that into the kinematics formula above to get a speed of about 7.9 m/s after crossing the 4m surface. then i used momentum to figure out the height of the ball in the pendulum. Before the collision the momentum was mass of block (5 kg) times speed (abt 7.9 m/s). I setup the formula for the collison like this momentum before = 5kg x (approx. 7.9m/s) after the collision the block was moving at 3 m/s momentum after = 5 kg x (3 m/s) + 2.5(v(of ball a)) since momentum is conserved i solved the equation to find v of ball a which was about 9 m/s. i then used the kinetic energy formula to find the energy at that point right after the collision. At this point kinetic energy was at a max and potential energy was at a minimum. I then converted the energy to potential which would have happened when the pendulum swung to one side. I used the formula Ep = mgh to finally find the height of the ball which i got to be around 5meters (4.9 something) I am not sure if this was correct way of doing it. I saw a similar question elsewhere and saw that the answers were somewhat different. i wanted to know if i was right in the way i did it, the asnwer did seem reasonable to me. |
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| Jan16-12, 03:23 PM | #2 |
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I have not checked any of your maths calculation but I cannot find anything wrong with your method
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| Jan16-12, 03:30 PM | #3 |
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| Jan16-12, 03:39 PM | #4 |
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object sliding down horizontal, frictionless slope, crossing horizontal surface
It looks correct. But keep at least 3 significant digits in the intermediate results .
ehild |
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