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Trend in Square roots question [Curious Math Newb question] 
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#1
Jan1912, 08:12 PM

P: 184

I noticed that 2 grows by 2 when it is squared, and 3 grows by 6 when it is squared, and 4 grows by 12, and 5 grows by 20... etc. etc.
So 3's increase when squared is 4 more than 2's increase when squared, and 4's increase when squared is 6 greater than 3's increase when squared, and 5's increase when squared is 8 bigger than 4's......... etc. etc... <The change from 45 is 2 bigger than the change from 34, and so on.. Why does this trend exist? Does it mean anything? Thanks guys 


#2
Jan1912, 08:31 PM

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P: 12,447

Well lets see...
It helps to be able to write number relations as math vis: the increase in a number n when you square it is given by  [itex]I_n=n^2n[/itex] the difference in the adjacent increases would be: [itex]D_n=I_nI_{n1}[/itex] which would be:[tex]D_n=\big [ n^2n \big ]  \big [ (n1)^2  (n1) \big ] = 2(n1)[/tex]... which is linear. That what you mean? 


#3
Jan1912, 08:56 PM

P: 184

The second part of my post was trying to say D_{n}  D_{n1} = 2 and that can be found by 2(n1)  2(n11) = 2! 


#4
Jan1912, 09:27 PM

P: 437

Trend in Square roots question [Curious Math Newb question]
Notice also the same linearity in the simpler progression 9  4 = 5, 16  9 = 7, 25  16 = 9 ...
If you grasp visual concepts more easily, look at this: The multicoloured square on the left represents your original series, that on the right represents the simpler one mentioned above. In each case the two red squares are the difference between successive terms (in this case 6^{2} and 7^{2})  notice that in each large square the green and blue Lshapes are congruent. 


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