# Trend in Square roots question [Curious Math Newb question]

Tags: curious, math, newb, roots, square, trend
 Homework Sci Advisor HW Helper Thanks ∞ P: 12,356 Well lets see... It helps to be able to write number relations as math vis: the increase in a number n when you square it is given by - $I_n=n^2-n$ the difference in the adjacent increases would be: $D_n=I_n-I_{n-1}$ which would be:$$D_n=\big [ n^2-n \big ] - \big [ (n-1)^2 - (n-1) \big ] = 2(n-1)$$... which is linear. That what you mean?
 Quote by Simon Bridge Well lets see... It helps to be able to write number relations as math vis: the increase in a number n when you square it is given by - $I_n=n^2-n$ the difference in the adjacent increases would be: $D_n=I_n-I_{n-1}$ which would be:$$D_n=\big [ n^2-n \big ] - \big [ (n-1)^2 - (n-1) \big ] = 2(n-1)$$... which is linear. That what you mean?