|Jan20-12, 12:23 PM||#1|
Equilibrium of three suspended blocks
1. The problem statement, all variables and given/known data
The problem(s) are shown in the link, but I'm having trouble getting them started.
2. Relevant equations
3. The attempt at a solution
I think what I need to do is find the tension force in the ropes leading from each block to point A. Then with those forces I find the Sum of the forces in X and Y
From there i think i know what to do, its just that i dont know how to find the force in each rope!
For block B, the force in the the rope to point A is sin∅/200lb. For block C, the force in the rope to point a is sin(30)/100 =50lb .
Is this correct so far?
|Jan20-12, 12:35 PM||#2|
Blog Entries: 1
Careful how you write things: don't confuse sin(30)/100 with 100*sin(30).
|Jan20-12, 04:02 PM||#3|
The tension in the ropes are equal to the weight of the blocks, so rope AB is 200lb and AC is 100lb.
Then I find the Sum of forces for X and Y and solve for the unknowns!
|blocks at rest, coplanar forces, equilibrium, three blocks|
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