## Sound Intensity Level and Hearing Problem

Thank you for the help!
 Could really use some input!

Recognitions:
Homework Help
 Quote by Dr. S Could really use some input!
It's correct, but I would've just used the inverse square law to work out the sound intensity at 2m from the one at 3m instead of calculating the power of the source.

## Sound Intensity Level and Hearing Problem

 Quote by Curious3141 It's correct, but I would've just used the inverse square law to work out the sound intensity at 2m from the one at 3m instead of calculating the power of the source.
Inverse square law? How I would I go about using that here?

Thank you, by the way. :)

Recognitions:
Homework Help
 Quote by Dr. S Inverse square law? How I would I go about using that here? Thank you, by the way. :)
$\frac{I_{2m}}{I_{3m}} = \frac{3^2}{2^2}$.

And you're welcome.