Integrating tan^2(u)(sec(u))du: Is There a Clean Way?

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SUMMARY

The integral of tan²(u)sec(u)du can be approached by converting it into a form involving only sine and cosine, specifically ∫(sin²(u)/cos³(u))du. Integration by parts is effective when applied correctly. A natural substitution, x → sinh(y), simplifies the integral ∫(x²/sqrt(x²+1))dx to ∫sinh²(y)dy. Utilizing hyperbolic trigonometric identities allows for the extraction of the integral, ultimately leading to the result after substituting back y → arg sinh(x).

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whats the integral of tan^2(u)(sec(u))du?

i was trying to integrate
(x^2)/sqrt(x^2+1)dx, and came into that. it turns out pretty messy though, is there a clean way to do it?
 
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Hi, I'm usually inclined to convert an integral like that to one with only sin's and cos's:

[tex]\int\frac{\sin(u)^2}{\cos(u)^3}du[/tex]

Integration by parts will work on this if you break it up properly.
 
[tex]\int \frac{x^{2}}{\sqrt{x^{2}+1}} dx =...?[/tex]
Make the natural substitution:[itex]x\rightarrow \sinh y[/itex]

U'll be gettin' [tex]\int \sinh^{2}y dy[/tex] (1)
Consider the "sister integral" [tex]\int \cosh^{2}y dy[/tex] (2)

Consider the two expressions obtained by:(2)+(1);(2)-(1).The two new integrals will be trivials since u can use the 2 formulae from hyperbolic trigonometry:
[tex]\cosh^{2}y-\sinh^{2}y=1;\cosh^{2}y+\sinh^{2}y= \cosh{2y}[/tex]

In the end u can extract this integral [tex]\int \sinh^{2}y dy[/tex] easily and then in the final result u'll have to make the substitution back
[tex]y\rightarrow \arg\sinh x[/tex]

Daniel.
 

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