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Help I need to find out whether activation energy can be calculated this way...? |
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| Feb2-12, 01:28 PM | #1 |
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Help I need to find out whether activation energy can be calculated this way...?
i did an experiment, i noted the tempreture and found rate constant.
My friend did the same experiment and she found rate constant and noted the tempreture.. The tempreture differs by one degree. Can i calculate tempreture like this...? S2O82-(aq) + 2 I-(aq) SO42-(aq) + I2(aq) Friend: K1: 0.0594 at t1: 21oC = 294 K Ours = K2: 0.06 and t2: 22oC. 295 K In (0.0594 /0.06) = Ea / 8.314 x ( 1/ 294- 1/295 ) -0.01 = Ea / 8.31 x (1.153x10-5) Ea= 0.01x 8.31 / 1.153x10-5) Ea = 7207.28 J/mol = 7.207 KJ mol Is this possible? please help me!! :( So for this reaction is the Ea 7.207 I would have done Just used my rate constant and tempreture to wwork out Ea but I dont know the Frequency factor A! I cant find this anywhere... |
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| Feb2-12, 01:42 PM | #2 |
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can anyone help me is this possible?
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