Complex Numbers - Forms and Parts


by dotNet
Tags: complex number
dotNet
dotNet is offline
#1
Feb11-12, 05:20 PM
P: 2
Hi, I have a complex number and understand that the rectangular form of the number is represented by

s = σ + jω, where σ is the real part and jω is imaginary.

I am having trouble locating them in the number below:
http://i44.tinypic.com/20koboi.png

I know that "2" is a real number, and the numerator is imaginary along with j*2*pi*k. Since the numerator is dividing both the elements at the bottom, does this number have a real and imaginary part? (This is where I am a little confused).

My guess would be that σ = 2 and the rest is imaginary.

If I could figure out what parts are real and imaginary, I can go on to find the rectangular form and the polar form.

Thanks
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SteveL27
SteveL27 is offline
#2
Feb11-12, 07:08 PM
P: 799
Quote Quote by dotNet View Post
Hi, I have a complex number and understand that the rectangular form of the number is represented by

s = σ + jω, where σ is the real part and jω is imaginary.

I am having trouble locating them in the number below:
http://i44.tinypic.com/20koboi.png

I know that "2" is a real number, and the numerator is imaginary along with j*2*pi*k. Since the numerator is dividing both the elements at the bottom, does this number have a real and imaginary part? (This is where I am a little confused).

My guess would be that σ = 2 and the rest is imaginary.

If I could figure out what parts are real and imaginary, I can go on to find the rectangular form and the polar form.

Thanks
Euler's relation e^ix = cos(x) + i*sin(x) vastly simplifies the exponential in the numerator. Cos and sin have period 2pi so the numerator is -1. Then multiply numerator and denominator by the conjugate of the denominator (assuming k is real). That leaves you with a real number in the denominator and a complex number in the numerator whose real and imaginary parts can be readily evaluated.

By the way, multiplying numerator and denominator by the conjugate of the denominator is the standard thing to do with this kind of problem.
HallsofIvy
HallsofIvy is offline
#3
Feb12-12, 07:58 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,879
Quote Quote by dotNet View Post
Hi, I have a complex number and understand that the rectangular form of the number is represented by

s = σ + jω, where σ is the real part and jω is imaginary.

I am having trouble locating them in the number below:
http://i44.tinypic.com/20koboi.png

I know that "2" is a real number, and the numerator is imaginary along with j*2*pi*k.
No, the numerator is NOT imaginary. In fact it is real- it is [itex]e^{j3\pi}= cos(3\pi)+ jsin(3\pi)= -1[/itex].
Since the numerator is dividing both the elements at the bottom, does this number have a real and imaginary part? (This is where I am a little confused).

My guess would be that σ = 2 and the rest is imaginary.

If I could figure out what parts are real and imaginary, I can go on to find the rectangular form and the polar form.

Thanks

RamaWolf
RamaWolf is offline
#4
Feb13-12, 01:08 AM
P: 96

Complex Numbers - Forms and Parts


Just try a look into www.wolframalpha.com and enter

Exp[3 Pi I] / (2 + 2 Pi k I)

what is the Mathematica version of your formula
Deveno
Deveno is offline
#5
Feb13-12, 07:46 AM
Sci Advisor
P: 906
as others have suggested, evaluate the numerator at the specific angle (3pi), and then multiply the resulting fraction by:

[tex]\frac{2 - j2\pi k}{2 - j2\pi k} (= 1)[/tex]

to make the denominator real.
alphachapmtl
alphachapmtl is offline
#6
Feb21-12, 07:54 PM
P: 81
Quote Quote by RamaWolf View Post
Just try a look into www.wolframalpha.com and enter

Exp[3 Pi I] / (2 + 2 Pi k I)

what is the Mathematica version of your formula
http://i44.tinypic.com/w8lqg6.png
http://i44.tinypic.com/w8lqg6.png


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