
#1
Feb2212, 09:37 AM

P: 33

I have made an Ottos Cycle graph and found the area W_{net} and W_{12}. I now have to find the efficiency η = W_{net}/W_{12} I have found that to be 0,20 but I have no idea what this tells me about the work or anything.
I need help. 



#2
Feb2312, 01:52 AM

P: 8

If [itex]\eta[/itex]=.2 then the system is 20% efficient, that is, if you put some energy into the system, only 20% of that energy is converted into work, and the other 80 percent is lost as heat.



Register to reply 
Related Discussions  
Otto Cycle: net work done  Advanced Physics Homework  4  
Thermodynamics: Otto Cycle  Engineering, Comp Sci, & Technology Homework  9  
Otto cycle  Engineering, Comp Sci, & Technology Homework  1  
Adiabatics with OTTO CYCLE  Introductory Physics Homework  3  
The Otto Cycle  Classical Physics  4 