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Mechanics - work done conservation of energy *Help needed* |
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| Feb26-12, 10:57 AM | #1 |
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Mechanics - work done conservation of energy *Help needed*
1. The problem statement, all variables and given/known data
A train with a mass of 250 tonnes starts from rest and accelerates up an incline of 1 in 100 attaining a speed of 45 Kph after traveling 200m. If the frictional resistance to motion is constant at 30KN calculate the work done by the engine using the principle of conservation of energy 2. Relevant equations Possible relevant equations: Work done= Force*Distance Force=Mass*acceleration Kinetic energy = 1/2*Mass*Velocity^2 Potential energy= Mass*Gravity (9.81)* Height 3. The attempt at a solution Force= 250*103 Kg*12.5= 3 125 000 kg/m/s Work done= 3 125 000*200= 625 000 000(J) Not sure whether this is along the right lines or not. I am also unsure where the frictional resistance and gravity is used. Thank you for your time. |
| Feb26-12, 10:48 PM | #2 |
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| Feb27-12, 09:39 AM | #3 |
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Sorry to be a pain, but I do not know how to go about this, please can you explain?
Thank you |
| Feb27-12, 09:58 AM | #4 |
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Mechanics - work done conservation of energy *Help needed*
Say, Eddy, if you are asked to solve the problem using energy methods, you should know about the possible energy equations to use, for example, you should know that the work done by non conservative forces (like the engine force and friction force in this example) must equal the change in PE plus the change in KE of the system. Give it a try.
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