Adiabatic compression of gas at two temperatures


by Kalus
Tags: adiabatic, compression, temperatures
Kalus
Kalus is offline
#1
Feb28-12, 08:58 AM
P: 37
I have a system that looks like this:



The top part is a piston, whereas the bottom is a displacer.

I have looked at the Isothermal case for this system in a separate thread (http://www.physicsforums.com/showthread.php?t=553165)

But in short, the result was that the pressure of the system is equal to:

[tex]m=m_{gc}+m_{gh}[/tex]
[tex]P=\frac{mR}{V_{gc}/T_c +V_{gh}/T_h}[/tex]

How can I modify this to take into account the temperature rise caused by adiabatic compression? I suppose I need to write the T_gc + T_gh as functions of the compression by the top piston, but how?
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