Proving with mean value theorem

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SUMMARY

The discussion focuses on applying the Mean Value Theorem to prove that if g(a) = g'(a) = 0 and |g''(x)| < M for all x in [a, a+h], then |g(a+h)| < Mh². The key steps involve letting k be any number in the interval [0, h] and utilizing the Mean Value Theorem on g' over the interval [a, a+k]. This leads to a definitive conclusion about the behavior of the function g in the specified conditions.

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  • Knowledge of derivatives and their definitions
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Suppose that g(a) = g'(a)=0 and |g''(x)| < M for all x in [a, a+h] (for some positive constant M). Show that |g(a+h)| < Mh^2.
(Hint: Let k be any number such that 0<= k <= h and apply Mean Value Theorem to g' on [a,a+k].)
 
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Well, what does the mean value theorem say, and what does it imply when you use it as hinted?
 
I'd also keep in mind the definition of a derivative.

--J
 

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