Connection coefficients as derivatives of parallel propagatorby ianhoolihan Tags: coefficients, connection, derivatives, parallel, propagator 

#1
Mar2512, 07:33 PM

P: 145

Hi all,
I've been fiddling around with this problem for a while. I intuitively understand that the parallel propagator is the path integral of the connection. I would like to be able to show the converse (connection is derivative of parallel propagator) mathematically, and I am having a little trouble. I've been thinking of the parallel propagator as in http://en.wikipedia.org/wiki/Paralle...llel_transport. I understand how to formulate the covariant derivative [tex] \nabla_X V = \lim_{h\to 0}\frac{\Gamma(\gamma)_h^0V_{\gamma(h)}  V_{\gamma(0)}}{h} = \frac{d}{dt}\Gamma(\gamma)_t^0V_{\gamma(t)}\Big_{t=0}. [/tex] (Actually not really the second equality  is this letting [itex]V_{\gamma(0)}=\Gamma(\gamma)_0^0V_{\gamma(0)}[/itex]?) However, the above link doesn't really show what the connection is. Yet, if you evaluate the last term of the above equation, then using the product rule you've got a term with the derivative of [itex]V[/itex] and a term with the derivative of the parallel propagator. This is what you'd expect for the covariant derivative of a vector, where the connecton coefficients are the derivatives of the parallel propagator. Nonetheless, I'm unable to make this all work out mathematically, so I was wondering if anyone could give me a hint? That is, on how the connection coefficients are the derivatives of the parallel propagator. Cheers. 



#2
Mar2612, 03:39 PM

P: 145

Well it looks like lots of people have viewed this thread, so I guess that means some interest. Can anyone shed some light, or offer a suggestion?
Cheers 


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