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Rearranging Equations to y= mx + b

 
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Mar29-12, 01:04 PM   #1
 

Rearranging Equations to y= mx + b


1. The problem statement, all variables and given/known data
Graph the following charts on excel so you have a linear relationship.
Determine your x and y variables before graphing, you may have to rearrange and even recalculate some of the variables.

Angle Period (s)
0 0.95
10 0.94
20 0.97
30 1.00
40 1.03
50 1.09
60 1.14
NOTE: TEACHER SAID THAT SHE GAVE THE WRONG NUMBERS, THESE WONT WORK, JUST GIVING THEM INCASE ANYONE ASKS.

2. Relevant equations

T=2π√(lcosα/g)
Fixed l of 1.0 m
What is g?



3. The attempt at a solution

Firstly, I have to get rid of the square root

T^2 = 4π^2cosx/g
I removed the l since it is equal to 1 and is a constant

The problem is here already. What can I do to make it a linear function. The moment i squared the T it became a quadratic/ arc.

I KNOW it isnt much, but i am struggling for so long and cant seem to get anywhere. Sorry about that guys.
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Mar29-12, 01:36 PM   #2
 
Mentor
Quote by Ranjan1995 View Post
1. The problem statement, all variables and given/known data
Graph the following charts on excel so you have a linear relationship.
Determine your x and y variables before graphing, you may have to rearrange and even recalculate some of the variables.

Angle Period (s)
0 0.95
10 0.94
20 0.97
30 1.00
40 1.03
50 1.09
60 1.14
NOTE: TEACHER SAID THAT SHE GAVE THE WRONG NUMBERS, THESE WONT WORK, JUST GIVING THEM INCASE ANYONE ASKS.

2. Relevant equations

T=2π√(lcosα/g)
Fixed l of 1.0 m
What is g?



3. The attempt at a solution

Firstly, I have to get rid of the square root

T^2 = 4πcosx/g
I removed the l since it is equal to 1 and is a constant

The problem is here already. What can I do to make it a linear function. The moment i squared the T it became a quadratic/ arc.

I KNOW it isnt much, but i am struggling for so long and cant seem to get anywhere. Sorry about that guys.
In the beginning of your problem statement, you mention x and y. But then in the equation there is no "y". Is x the independent variable in the equation? If so, what is the dependent variable?
Mar29-12, 03:09 PM   #3
 
T is the dependent variable
Mar29-12, 03:13 PM   #4
 
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Rearranging Equations to y= mx + b


So you mean x and T rather than x and y?
Mar29-12, 03:15 PM   #5
 
Yes, sorry.
Mar29-12, 04:30 PM   #6
 
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Well I could be wrong, but I don't think you can fit a linear equation to the T = SQRT(cos(x)) equation that you are given. Are you maybe supposed to find the best linear fit across some small interval of x?
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angles, equations, gravity, linear, physics
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