Transformers - Variation in Current, EMF and Magnetic FLux

This question about the variation of the aforementioned quantities in a transformer.

Now according to me and my knowledge of electricity this is how I feel it should play out :

If the input current were a sine curve that varies with time then :

Input voltage = cosine curve i.e. it is ahead of input current by 90 degrees.

Magnetic Flux = sine curve with same period as input voltage but LARGER amplitude.

Output voltage = out of phase with input voltage by 180 degrees.

Output current = this is where I'm faltering and I'm having issues....

Could someone please confirm what I've said is correct and help me with the bit in bold ?
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 Could someone also confirm if voltage = rate of change of current with time ?
 Bump.

Transformers - Variation in Current, EMF and Magnetic FLux

Hmmmmmm....interesting question.

I don't know the exact answer...but will just throw out some thoughts.

I know if you have a purely resisitive load hooked to a transformer.....the voltage and current appear to be in perfect phase on the secondary.....and primary. But as you are saying...the primary and secondary should be out of phase by 180 degrees since the secondary pumps current the other direction.

But the coil's inductive property says it will lag the current behind the voltage......

I'll be interested to see what the smart guys have to say.
 Are you considering a ideal transformer with a load or A NON ideal transformer with no load? A NON ideal transformr with a load will have answers to your question that depend on the load.

 Quote by Carl Pugh Are you considering a ideal transformer with a load or A NON ideal transformer with no load? A NON ideal transformr with a load will have answers to your question that depend on the load.
You have to understand that I'm an A Level student i.e. the equivalent of an American High School student.

Anyways, we've only been considering IDEAL transformers where we are told the is a Primary coil voltage and secondary coil voltage. We are never shown the presence of a load.

So, I'm guessing I want to know about an IDEAL transformer with NO load ?

 Quote by elemis You have to understand that I'm an A Level student i.e. the equivalent of an American High School student.
In that case, this question should be answered in Homework section.

Anyway.. In academic approach an "ideal transformer" means that:
- we neglect the resistance of the windings -> the transformer has efficiency equal to 1 (Pin = Pout),
- we assume that the schematic of transformer contains only two coils (primary and secondary),
- current and voltage on both sides are connected only by turn ratio of coils,
- all waveforms (current, voltage, flux) are assumed to be sinewave,

Flux can be calculated from Faraday's law of induction. In this case (only inductances in schematic of transformer) we have:

Uprimary - 0 deg
Flux and I primary - 90 deg
U secondary - 180 deg
I secondary and counter flux - 270 deg
 Quote by elemis Magnetic Flux = sine curve with same period as input voltage but LARGER amplitude. ?
Please tell me, how can You compare amplitude of flux and voltage ? Volts vs Webers ? Amplitude of flux depends on voltage and magnetic circuit as said below:

Induction * Cross.section = Flux = Voltage / (4,44 * Frequency * Turn.ratio)

That's in theory - means BIG simplifications.

 Quote by gerbi In that case, this question should be answered in Homework section.
Well, this isnt a homework question. Its me trying to further my knowledge in the subject.

 Quote by gerbi Anyway.. In academic approach an "ideal transformer" means that: - we neglect the resistance of the windings -> the transformer has efficiency equal to 1 (Pin = Pout), - we assume that the schematic of transformer contains only two coils (primary and secondary), - current and voltage on both sides are connected only by turn ratio of coils, - all waveforms (current, voltage, flux) are assumed to be sinewave, Flux can be calculated from Faraday's law of induction. In this case (only inductances in schematic of transformer) we have: Uprimary - 0 deg Flux and I primary - 90 deg U secondary - 180 deg I secondary - 270 deg
What do you mean by U Primary ? Is that the voltage across the primary coil ? Do you mean 90 degrees ahead of U Primary or lagging behind ?

 Quote by elemis What do you mean by U Primary ? Is that the voltage across the primary coil ? Do you mean 90 degrees ahead of U Primary or lagging behind ?
Uprimary is primary voltage (on primary coil).
Leading or lagging ? We consider coils here - currents are lagging.

 Quote by gerbi Uprimary is primary voltage (on primary coil). Leading or lagging ? We consider coils here - currents are lagging.
To be honest you're only confusing me.

Could you have a look at my post and tell me whether what I've said is correct or wrong ?

 Quote by elemis To be honest you're only confusing me. Could you have a look at my post and tell me whether what I've said is correct or wrong ?
That's why this questions should be answered in Homework section.

Uprimary means voltage measured between both terminals of a coil.

Currents in both windings are 90 deg behind voltages (currents are lagging).
 In an ideal transformer with no load: There would not be any primary or secondary current. Magnetic flux would lag the applied voltage by 90 degrees. Magnetic flux and voltage are in different units, so you cannot say one is larger than the other. Output voltage phase depends on how the transformer is connected. Some engineers might say that input voltage and output voltage are 180 degrees out of phase. I consider output voltage and input voltage in phase.

 Quote by Carl Pugh In an ideal transformer with no load: There would not be any primary or secondary current. Magnetic flux would lag the applied voltage by 90 degrees. Magnetic flux and voltage are in different units, so you cannot say one is larger than the other. Output voltage phase depends on how the transformer is connected. Some engineers might say that input voltage and output voltage are 180 degrees out of phase. I consider output voltage and input voltage in phase.
They are techinically out of phase by 180 degrees.....but who cares? So what you are saying is more or less true. When you hook up your load to your secondary....the voltage and current are in phase....and the reference point of you voltage is what it is. Referring back to the primary phase of the voltage doesn't do you any good unless you are playing with math. In the field....this info won't help you.

To elemis.......since you are at a high school level....keep things simple. The turns ratio.....power in = power out.....and the formula for computing the resistance from the secondary back to the primary should be all you need at this point. Until these things are mastered.....don't move on quite yet.
 Recognitions: Gold Member Science Advisor Some high schools teach enough calculus to have covered that derivative of a sinewave is a cosine wave. My high school did not. At least before 12th grade. Our Electronics teacher taught us 10th grade boys that sine and cosine waves are same shape but shifted 90deg and we worked the circuit problems using operator j which shifted 90 degrees. So two 90 degree phase shifts = 180 deg phase shift, which reverses polarity, which is same as multiplying by -1, so operatorj we thought of as √-1. We worked our problems in simple algebra using rectangular and polar notation . Became skilled at conversions by slide rule . We had one guy in class who was somewhat of a prodigy and he worked the problems via math resembling Eueler's identity . He was way ahead of us ordinary kids. So if you haven't taken calculus yet that's okay, you will. Meantime i'm sure you are aware the cosine wave is a plot of the slope of a sine wave and vice versa. Your understanding of the transformer is pretty good. Re polarity we indicate polarity on a schematic diagram by dots on the ends of the windings that go positive at same time. In practice you find it with a battery and multimeter. Point of all this - you seem to have a good start ! Curiosity - are you taking an electronics course in high school or is this your own hobby? old jim

 Quote by jim hardy Some high schools teach enough calculus to have covered that derivative of a sinewave is a cosine wave. My high school did not. At least before 12th grade. Our Electronics teacher taught us 10th grade boys that sine and cosine waves are same shape but shifted 90deg and we worked the circuit problems using operator j which shifted 90 degrees. So two 90 degree phase shifts = 180 deg phase shift, which reverses polarity, which is same as multiplying by -1, so operatorj we thought of as √-1. We worked our problems in simple algebra using rectangular and polar notation . Became skilled at conversions by slide rule . We had one guy in class who was somewhat of a prodigy and he worked the problems via math resembling Eueler's identity . He was way ahead of us ordinary kids. So if you haven't taken calculus yet that's okay, you will. Meantime i'm sure you are aware the cosine wave is a plot of the slope of a sine wave and vice versa. Your understanding of the transformer is pretty good. Re polarity we indicate polarity on a schematic diagram by dots on the ends of the windings that go positive at same time. In practice you find it with a battery and multimeter. Point of all this - you seem to have a good start ! Curiosity - are you taking an electronics course in high school or is this your own hobby? old jim
Actually, this is simply part of the A Level (British Curriculum) syllabus for Physics.
 I know that this is starting an argument like discussing politics or religion, but what the heck. I say the polarity of the input winding is the same as the output winding because. You can wind a transformer with two wires at the same time. (bifilar winding) The start of both wires can be connected together and the end of both wires can be connected together. This winding can be used as the primary (or secondary) of the transformer. Thus both wires have the same polarity. Now you can disconnect one wire and have a secondary. The polarity hasn't changed, so the polarity of the primary and the secondary is the same.

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Gold Member
 Actually, this is simply part of the A Level (British Curriculum) syllabus for Physics.
I was in high school in 1961-1964.

Sounds like your physics is more comprehensive than was ours.
That's good. This is the age of technology and i believe education system should prepare us for the world we live in. The high school i attended was experimenting with that concept. I was very fortunate. It gave me a running start at engineering school.

We also studied a year of English Literature. Does your syllabus include any American lit ?

old jim

 Tags alternating current, emf, transformers, voltage