Question about vectors with electric field equations

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SUMMARY

The discussion centers on the application of the electric field equation E = (kq)/(R)^2 in vector form, specifically addressing the confusion around the sign of the vector. The electric field vector is defined as 𝑬 = (q / (4π𝜖₀𝜖ᵣ |𝑟|²)) (𝑟 / |𝑟|), where the direction of the vector aligns with the path from the charge to the field point, adjusted by the charge's sign. The example provided involves calculating the electric field at point (1,1) due to a charge located at the origin.

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  • Understanding of electric field equations and vector notation
  • Familiarity with Coulomb's law and its applications
  • Basic knowledge of coordinate systems in physics
  • Concept of electric charge and its properties
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This discussion is beneficial for physics students, educators, and anyone involved in the study of electromagnetism, particularly those seeking clarity on vector directions in electric field equations.

LakeMountD
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Using the equation E= (kq)/(R)^2 in the r direction. I am confused on when to make the vector negative in my equations. For instance if you had a charge on x=0 and x=5 (on the x axis) and then you want to find the field at point (1,1) or something like this.
 
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Consider an electric charge "q" in the origin of the coordinate system.The electric field at at a point of coordinate vector [tex]\vec{r}[/tex] is

[tex]\vec{E}=\frac{q}{4\pi\epsilon_{0}\epsilon_{r}|\vec{r}|^{2}}\frac{\vec{r}}{|\vec{r}|}[/tex]

That's all.

Daniel.
 
The direction of the vector is the same as the direction from the source point to the field point - multiplied by the sign of the charge.
 

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