Solving Integral: \int{\sqrt{{4-2x^2}}}dx

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Discussion Overview

The discussion revolves around solving the integral \(\int{\sqrt{{4-2x^2}}}dx\). Participants explore various methods of integration, including substitutions and transformations, while addressing potential complications and clarifications regarding the problem's domain.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty in solving the integral using Euler's substitution, seeking a simpler solution.
  • Another participant suggests rewriting the integral as \(\int 2\sqrt{1-(\frac{\sqrt{2}x}{2})^{2}} dx\) and proposes a sine substitution.
  • A different approach is presented, factoring out a "2" to simplify the integral and using a trigonometric substitution involving \(\sin(\theta)\).
  • One participant corrects a previous statement about the cosine function, emphasizing the absolute value in the expression \(\sqrt{1-\sin^{2}\theta}=|\cos\theta|\).
  • There is a discussion about the importance of stating the domain of \(x\) in the initial problem, with some participants suggesting that it could complicate the solution unnecessarily.
  • Several participants engage in a light-hearted exchange about the word "alambicated," with one noting its translation from Romanian and another providing a definition.

Areas of Agreement / Disagreement

Participants present multiple competing views on how to approach the integral, and there is no consensus on a single method or the necessity of clarifying the domain of \(x\). The discussion remains unresolved regarding the best approach to the integral.

Contextual Notes

Some participants note the potential complications of defining the domain of \(x\) and the implications this may have on the solution, but these points remain open for further discussion.

pa1o
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Iam having trouble how to solve

[tex]\int{\sqrt{{4-2x^2}}}dx[/tex]

When I try eulers substitution, the integral gets only terribly complicated and all..

Anyone can help me out with a simple and nice solution ?
 
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How about
[tex]\int 2\sqrt{1-(\frac{\sqrt{2}x}{2})^{2}} dx[/tex]

and the substitution
[tex]\frac{\sqrt{2}x}{2}\rightarrow \sin u[/tex]

Daniel.
 
I would have done it a slightly different way (mostly because I don't like fractions!): factor out a "2" (instead of "4" as dextecioby does) to get
[tex]\sqrt{2}\int\sqrt{2- x^2}dx[/tex]
Now let [itex]x= \sqrt{2}sin(\theta)[/itex] so that [itex]2- x^2[/itex] becomes [itex]2- 2sin^2(\theta)[/itex] and [itex]\sqrt{2- x^2}= \sqrt{2(1- sin^2(\theta)}= \sqrt{2 cos^2(\theta)}= \sqrt{2}cos(\theta)[/itex]. Of course, [itex]dx= \sqrt{2}cos(\theta)[/itex]. You wind up with exactly the same thing as dextercioby's way.

Generally speaking, any time you see something that looks like [itex]\sqrt{1- x^2}[/itex] you should think "[itex]\sqrt{1- sin^2(\theta)}= cos(\theta)[/itex]
 
Just a tiny, but rather important correction:
[tex]\sqrt{1-\sin^{2}\theta}}=|\cos\theta|[/tex]
 
How about stating the domain of "x" in the initial problem??In this case all real axis doesn't pose problems,but it could have been only the positive semiaxis and Halls's post would have been flawless (alambicated,but flawless :-p )...


:-p

Daniel.
 
WOW!
I've just learned a new English word: "alambicated" :smile:
Now, I need to figure out where I can use it..
 
I vritually translated the word from Romanian ("alambicat") into English,without really knowing it would exist or not.I searched it with google and came up with 2 references...If the endings ".no (Norway?? :-p )" and ".es" (Spain) are correct,then it's a brand new word in the English language...

Daniel.

P.S.I wish i had invented it... :cry:
 
I found the following definition in an on-line dictionary:
"alembic
n. ancient distilling apparatus; purifying or transforming apparatus or act. alembicate, v.t. distil. alembicated, a. rather too refined (of literary style).


© From the Hutchinson Encyclopaedia.
Helicon Publishing LTD 2000.
All rights reserved."

(Still a new word to me, though :smile:)
 
dextercioby said:
How about stating the domain of "x" in the initial problem??

wtf why not just leave the | | s ?? it's just a little 1st-year calculus problem. why make things more complicated by doing that
 
  • #10
thanks people

THANK YOU all and thank you daniel and all the nice people who helped me :o)
 

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