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Direction of friction in rolling motion 
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#1
May2812, 03:23 PM

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I am really confused as to how to determine the direction of friction acting on a rolling object. Could someone help clarify how to determine the direction of friction? ANy help is appreciated ;)



#2
May2812, 03:39 PM

P: 349

The easiest thing to say is that friction opposes motion. May not be much help but it is where you must start



#3
May2812, 03:42 PM

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Think of an accelerating car...say increasing speed to the right.....a positive acceleration.
can you visulaize the direction of friction against the tires??...the 'gripping' between the road and the tire?? the tires are rotating clockwise....so the friction vector must oppose this at the road surface and point to the right.... If a car is decelerating what happens....as brakes are applied?? the force of friction must again help the tires 'grip'....but this time points towards the left. edit: just occurred to me....for steady velocity rolling friction....I could not tell for sure....looked it up: http://en.wikipedia.org/wiki/Rolling_friction 


#4
May2812, 04:00 PM

P: 13

Direction of friction in rolling motion
let's consider the problem when a ball initially at rest on a surface with friction is given a horizontal impulse. According to some online sources, the ball will eventually attain a maximum speed after it is given the impulse. However, this makes absolutely no sense to me; isn't the friction opposing the motion, causing the velocity to strictly decrease?



#5
May2812, 04:16 PM

P: 349

The ball being struck is not an easy problem!!!! depends where it is struck, any spin and friction.
A great book 'physics of ball games' ny Daish goes into great detail about the motion of (snooker) balls across surfaces. 


#6
May2812, 10:08 PM

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If the problem is described in terms of impulses, instead of F(t), it just means that you are integrating F(t) over time to get an impulse, and you are imagining that the time is very short. The logic is the same the impulse of lateral momentum, and the impulse of angular momentum, both have to be specified, and you then assert there is also an impulse of both from the friction, and its value is whatever is required to allow V=R*W to hold after the impulses have been applied. That will suffice to tell you the impulse of lateral momentum coming from friction (since the impulse of angular momentum will just be R times that, with whatever sign is required to make it all work which is the answer to your question). Note that after the impulses are over, the ball rolls at constant speed, and this will indeed be the maximum speed it attains. There is no static friction at this point, not in the idealized case. 


#7
May2912, 04:18 AM

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Perhaps the sources you cite are considering a force applied over some nonzero duration as the impulse, and 'eventually' refers to that duration. Or maybe they're referring to the rotational speed. 


#8
May2912, 05:00 AM

P: 349

If you consider a ball struck with a horizontal blow at the centre no initial rotation is imparted and the ball will begin to slide over the surface with an initial velocity, V.
A frictional force will come into play at the point of contact F = μMg where M is the mass of the ball and μ is the coefficient of sliding friction between the ball and the surface. (about 0.2 for snooker, billiard balls). This force has 2 effects....first it will produce linear decelleration of the ball = F/M = μg second....the moment of the force about the centre of the ball will produce an angular acceleration = torque/moment of inertia. = Fr/I = μMgr/I where r = radius of ball and I = moment of inertia of the ball about an axis through the centre. I = (2Mr^2)/5 angular acceleration = 5μg/2r After a time, t, the linear velocity will have decreased to v = V  μgt and the angular velocity will have reached a value ω = 5μgt/2r The ball will start rolling when v = ωr The above equations can be combined to show that atthis point the linear velocity = 5V/7 and the angular velocity = 5V/7r I hope this adds to the discussion The mathematics comes from 'the physics of ball games' by C B Daish 


#9
May2912, 05:54 AM

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#10
May2912, 06:12 AM

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Friction in this particular case would not neccessarily be in place. However, a counter force might be the more correct term to use. As a ball rolls on a surface, the ball and the surface will be deformed, causing the ball to roll in a pit that follows the ball. The pit will cause the ball to roll against a slight uphill  even if the ball is moving horizontally. The "friction" in this case does not have to result in heat loss (Which is friction in my understanding of the term). If heat loss is out if the equation, there must be a counterforce rather than friction. It can however be both friction and counterforce  if the ball and/or the surface consists of a soft material that permanently deform as it rolls.
Correct me if I'm wrong. EDIT: Super elastic materials might solely be slowing down due to counter force which is caused by the pit due to the weight of the ball on the surface. A ball of led would roll shorter than a ball made of nitinol or other super elastic materials. Vidar 


#11
May2912, 06:34 AM

P: 141

Hi david456103,
Here is the best way to find the direction of friction force. Its my own style. I think it would really help you. If you ever want to find the direction of friction force on any object, first think that friction is completely absent there. It happens somewhere on the completely wet muddy surface or say on any lubricant surface. Sometimes you might have seen any Tyre slipping on wet wet muddy surface. If you are able to assume this in your mind than think if the complete smooth surface on which the Tyre is slipping instantaneously becomes rough then in what direction friction will act. EX. See the attachment I have attached with this reply. In this figure assume the van is slipping on a oily surface. The engine of the vehicle makes the rear tyres rotate so the rear tyres will be rotating only not translating in front direction> the bottommost point of the rear tyre "A" will be in contact with the ground and slipping in the back direction. If the friction suddenly comes there, it'll act in the front direction. Same thing for the front tyre. There is no engine which rotates the tyre. So on the oily surface it'll only be slipping in the front direction not rotating. The contact point of the front tyre will be "B" and will be translating only in the front direction. If the friction comes suddenly, it'll act in the back direction. 


#12
May2912, 08:53 AM

P: 13

@truesearch i think you have the wrong problem in mind, but yeah your thinking process is exactly the one I feel is right.
Here is the problem I'm concerned about(from MITOCW): A spherical billiards ball of uniform density has mass m and radius R and moment of inertia about center of mass of (2/5)mR^2. The ball, initially at rest on a table, is given a sharp horizontal impulse by a cue stick that is held an unknown distance h above the centerline. The coefficient of sliding friction between the ball and the table is μ. You may ignore the friction during the impulse. The ball leaves the cue with a given speed v0 and an unknown angular velocity ω0. Because of its initial rotation, the ball eventually acquires a maximum speed of (9/7)v0(??????). Find h/R. The given solution uses angular momentum, which completely makes sense to me, but this problem does not make any conceptual sense to me. How can the ball increase in translational speed when there is friction? 


#13
May2912, 10:14 AM

P: 349

What I can add is where to hit a snooker ball to eliminate sliding (i.e. ball rolls)
To do this the ball is hit above centre at a height, h, above the table. To eliminate sliding the point of impact is known as the 'centre of percussion' It can be shown that the centre of percussion is given by (r + I/Mr) where I is the moment of inertia about an axis through the centre of the ball. so h = r + I/Mr and I = (2Mr^2)/5 gives h = r +(2Mr^2/5Mr) = 7r/5 or 7x(2r)/10 so to eliminate sliding the ball needs to be struck at a height above the table equal to 7/10 of the diameter. Again, the analysis is a summary of what is given in 'physics of ball games' hope it helps 


#14
May2912, 11:49 AM

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