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Pressure drop w.r.to time through a orifice dia(D) in a container of volume (V) |
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| Jun19-12, 01:53 AM | #1 |
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Pressure drop w.r.to time through a orifice dia(D) in a container of volume (V)
Let initial preasure (P) = 10 bar,volume of container (V)=100000 cubic cm.
At what time period pressure will become 5 bar. |
| Jun20-12, 12:47 AM | #2 |
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| Jun20-12, 06:28 AM | #3 |
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Recognitions:
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I make no guarantees for the correctness of this, but here's what I got.
Let vol of tank be V, pressure P(t), mass remaining in tank m(t), outlet area A, exit velocity f(t). In time dt, a volume A*f.dt, mass (Afm/V).dt, exits. Assuming adiabatic expansion: P(t+dt)(V+Af.dt)γ = P(t)Vγ, where γ = 1.4 whence P' = -PγAf/V m' = -fAm/V By conservation of energy (P-Pa)Af.dt = Af3m.dt/2V where Pa is ambient pressure. I forgot about Pa at first, and obtained (γ-1)At = ((P0/P)(1-γ)/2γ - 1)√(2Vm0/P0) where P0 = P(0), m0 = m(0). I might try to correct that tomorrow. |
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