Why Does Calculus Make f(x) Discontinuous?

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Homework Help Overview

The discussion revolves around the function f(x) = (2x-2)/((x^2)+x-2) and its points of discontinuity. Participants are exploring the conditions under which the function is discontinuous and the implications for limits at those points.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to identify values of 'x' that cause f(x) to be discontinuous, primarily by examining the denominator for zeroes. There is also discussion about determining limits at points of discontinuity and finding parameters for a related rational function.

Discussion Status

Some participants have expressed confidence in their understanding of parts A and B, while others are struggling with part C. There is a suggestion to factor the numerator and denominator to aid in understanding the problem.

Contextual Notes

One participant implies that understanding the discontinuity is straightforward, while another's comment suggests a lack of engagement with the material. The discussion reflects varying levels of familiarity with the concepts involved.

ashleyk
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Given the function f(x) by f(x) = (2x-2)/((x^2)+x-2)

A) For what values of 'x' is f(x) discontinuous?
B) At each point of discontinuity found in part A, determine whether f(x) has a limit and, if so, give the value of the limit.
C) A rational function g(x)= a/(b+x) is such that g(x)=f(x) wherever f(x) is defined. Find the values of 'a' and 'b'.

I think I figured out both part A and B, but part C is killing me. Any help would be great.
 
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ashleyk said:
Given the function f(x) by f(x) = (2x-2)/((x^2)+x-2)

A) For what values of 'x' is f(x) discontinuous?
B) At each point of discontinuity found in part A, determine whether f(x) has a limit and, if so, give the value of the limit.
C) A rational function g(x)= a/(b+x) is such that g(x)=f(x) wherever f(x) is defined. Find the values of 'a' and 'b'.

I think I figured out both part A and B, but part C is killing me. Any help would be great.
A function is discontinuous when the y value for a certain x value does not exist. In this case, it would be when the denominator equals zero. That should be pretty simple to figure out.
 
You must have skipped class not to get a).

Simon, from American Idol:

Like seriously, you skipped class and that shirt looks dirty awful.
 
For part C) have you tried factorising both numerator and denominator ? It should become fairly obvious then.
 

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