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How to draw a phasor addition on AC circuit? |
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| Jul16-12, 04:53 AM | #1 |
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How to draw a phasor addition on AC circuit?
1. The problem statement, all variables and given/known data
Two alternating currents are applied out of phase with each other. One is 4 volts and the other is 3 volts 27° out of phase. These can be written as (4, 0°) and (3, 27°) 2. Relevant equations a)draw both phasors b)draw the combined phasor between (0 degree and 360 degree) c)label peak voltage and state its value 3. The attempt at a solution a)A rough drawing on paint http://imageshack.us/photo/my-images/3/plotb.jpg/ b) I know A= 6.8106 volts by using this formula r=√a2+b2 r=3cos27 + 4i + i(3sin 27) r=√(3cos27 + 9)2 + (3sin27)2 =6.81v angle=0.2014 |
| Jul16-12, 11:49 AM | #2 |
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The drawing look OK, but I don't think you've got the right components. The real parts of the phasors are 4 and 3cos27 respectively. The imaginary parts are 0 and 3sin27 respectively.
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