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How to draw a phasor addition on AC circuit?

 
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Jul16-12, 04:53 AM   #1
 

How to draw a phasor addition on AC circuit?


1. The problem statement, all variables and given/known data

Two alternating currents are applied out of phase with each other. One is 4 volts and the other is 3 volts 27° out of phase.

These can be written as (4, 0°) and (3, 27°)


2. Relevant equations

a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value



3. The attempt at a solution

a)A rough drawing on paint http://imageshack.us/photo/my-images/3/plotb.jpg/

b) I know A= 6.8106 volts by using this formula

r=√a2+b2

r=3cos27 + 4i + i(3sin 27)

r=√(3cos27 + 9)2 + (3sin27)2

=6.81v

angle=0.2014
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Jul16-12, 11:49 AM   #2
 
Mentor
The drawing look OK, but I don't think you've got the right components. The real parts of the phasors are 4 and 3cos27 respectively. The imaginary parts are 0 and 3sin27 respectively.
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