| New Reply |
Simplifying the result of integration |
Share Thread | Thread Tools |
| Jul24-12, 02:03 PM | #1 |
|
|
Simplifying the result of integration
1. The problem statement, all variables and given/known data
The original problem is [itex] \int \, \frac {xe^{2x}}{(1+2x)^2} dx [/itex]. I utilized integration by parts to get: [itex] -\frac {xe^{2x}}{2(1+2x)} \, + \, \frac {1}{4}e^{2x} \, + \, C [/itex] which I know is correct. However, I am told by the book that this may also be expressed as: [itex] \frac {e^{2x}}{4(2x+1)} + C [/itex] It is a failing of my algebra skills that I am unable to make this translation. I have banged my head against this problem for close to an hour now. The truly frustrating thing is that it was very apparent to me yesterday (I was redoing the problem just to warm up for more i.b.p. problems), and I quickly wrote it down, but cannot seem to 'see' it today. Any help would be much appreciated. 2. Relevant equations none 3. The attempt at a solution I have tried expanding the denominator of the first term and factoring out the common [itex] \frac{1}{2} e^{2x} [/itex] but then I get stuck. In particular, I can't figure out how to deal with the x in the numerator and the negative sign. I think I'm pretty clearly forgetting/misapplying some algebraic rules, so the first thing in the way of suggestive assistance that might help would be just a reference to the relevant rules/ideas. I think that given such a push in the right direction I can figure this out on my own. Additionally, if anyone could suggest some resources for practice with algebra of this level of difficulty I'd greatly appreciate it. |
| Jul24-12, 02:24 PM | #2 |
|
|
Do you remember how to add/subtract fractions with different denominators? |
| Jul24-12, 02:24 PM | #3 |
|
Mentor
|
|
| Jul24-12, 03:04 PM | #4 |
|
|
Simplifying the result of integration
Awesome, thank you, I'm really not sure why that didn't click. I think I frequently miss the forest for the trees
![]() BTW, is the notion of a "simplified" related to how many operators have scope over the whole expression? i.e., here it went from two applications of "+" to just one. Just what is "simple" has never really been explained to me my satisfaction. Anyway, that's sort of asinine, but thanks again for your quick response and help with my problem! |
| Jul25-12, 01:28 PM | #5 |
|
Mentor
|
Where they might not agree is whether the factored form is simpler than the form I show. |
| New Reply |
| Thread Tools | |
Similar Threads for: Simplifying the result of integration
|
||||
| Thread | Forum | Replies | ||
| integration result varying in mathematica 5.2 | Calculus | 2 | ||
| integration result ln || - confusing and apparent contradictions! | Calculus | 4 | ||
| Simplifying changes integration | Calculus | 3 | ||
| Use double integrals to show result of integration by parts | Calculus & Beyond Homework | 8 | ||
| Simplifying 1/x(1-x) for integration | General Math | 2 | ||