|Jul29-12, 09:31 PM||#1|
Conservation of Angular Momentum Experiment: Moment of Inertia
1. The problem statement, all variables and given/known data
I did a lab where there was a rotating solid disk with mass= 0.915kg and diameter=0.253m.
This was rotating horizontally with an initial angular velocity of 3 different values ω radians/second. After recording the initial angular velocity, I dropped a thin-walled hollow cylinder with mass=0.708kg and diameter=0.125m in the center and measured the final angular velocity, testing the conservation of angular momentum.
Issue: If I placed the ring off center of the disk by say, 1cm (0.01m), how will that affect my moment of inertia?
2. Relevant equations
Lf=(Idisk+Ihoop/hollow cylinder)ωcombined final
3. The attempt at a solution
First, I calculated the moments of inertia-
The Icombined is for the ideal situation of the ring being completely centered, but I have no idea what I would do to get the experimentally flawed moment of inertia. Would I just change the radius of the hoop/cylinder by 1cm? If so, would I add or subtract? I'm really not sure how I'd calculate it. I understand this all generally pretty well, but executing this has me a little stumped. I need a way to get the new final moment of inertia instead of the ideal (Idisk+Ihoop/hollow cylinder) to calculate a percent error.
|Jul29-12, 10:16 PM||#2|
Hi, chrismoon. Have you studied the "parallel axis theorem"? You can use it to calculate the moment of inertia of the hollow cylinder when it is placed off-center on the disk.
|Jul29-12, 10:17 PM||#3|
have you used the parallel axis theorem?
late again, sorry. Its getting strange how I am right behind Tnsy.
I will now bow out again.
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