Register to reply

Integration involving trig. substitution

by Mangoes
Tags: integration, involving, substitution, trig
Share this thread:
Mangoes
#1
Jul31-12, 08:00 PM
P: 78
1. The problem statement, all variables and given/known data

See below.

2. The attempt at a solution

Hey there, apologies for doing so, but I don't know how to use latex on this board (it doesn't show me anything when I hit preview, so I had to make a picture for the sake of cleanness.

imgur.com/WzrAR.png

The first line is the original problem, with the proceeding lines being the attempt I made.

I have about four months before I transfer to a new university and figured I might as well self-study Calculus. I finished Calculus I without any trouble so I just started doing what I will eventually cover in Calculus II, but unfortunately my textbook offers only a mechanical way of doing this technique which leaves some doubt in my mind.

Is trigonometric substitution legal to do in any integral (regardless of whether it will actually help integrating) so long as you also substitute any related variables to the one you're substituting with? I've tried it out with simple indefinite integrals like ∫3x^2 dx but I'm unsure whether or not issues would occur if I substituted, for example, x = tan(θ) for ∫1/x due to the fact that 1/tan(θ) is undefined in an infinite amount of inputs while 1/x is undefined in only one.

Furthermore, I've looked over my work and I can't find any errors, so I don't know whether there's some concept I'm completely missing out on or there's some hidden error I just can't see.

Thanks for any input.
Phys.Org News Partner Science news on Phys.org
Suddenly, the sun is eerily quiet: Where did the sunspots go?
'Moral victories' might spare you from losing again
Mammoth and mastodon behavior was less roam, more stay at home
Dick
#2
Jul31-12, 08:19 PM
Sci Advisor
HW Helper
Thanks
P: 25,251
You are messing up in the integration by parts section. Otherwise, well done! You are partially ignoring the presence of the 9/4 factor. Try it this way. Just integrate sec^3 by parts. Add the 9/4 factor later.
Mark44
#3
Jul31-12, 08:29 PM
Mentor
P: 21,216
Your work looks good, and nothing immediately pops out at me. I think that you have a constant wrong somewhere.

I'll take a closer look and see if I can spot where the problem is.

I suppose trig substitution could be applied to any integral, but where it's most commonly used is where you have the square root of a sum or difference of squares. The radical can appear in the numerator, but commonly appears in the denominator.

The idea with trig substitution is to apply the substitution to get an integral that you can actually evaluate, so I don't see it used with cube roots, or the like, or with simple polynomials or power functions, as in your example.

LaTeX isn't hard to use. Here's the LaTeX for the integral you started with. To make it actually render, put a pair of $ signs at the beginning, and another pair at the end.

\int \sqrt{9 + 16x^2}dx

Edit: Dick beat me to it, so I won't take a closer look.

Mangoes
#4
Jul31-12, 09:08 PM
P: 78
Integration involving trig. substitution

Quote Quote by Dick View Post
You are messing up in the integration by parts section. Otherwise, well done! You are partially ignoring the presence of the 9/4 factor. Try it this way. Just integrate sec^3 by parts. Add the 9/4 factor later.
Thank you! I followed your suggestion and saw that the result I had was indeed different than what I had previously gotten. After multiplying that by 9/4, differentiating gives my original function.



Quote Quote by Mark44 View Post
Your work looks good, and nothing immediately pops out at me. I think that you have a constant wrong somewhere.

I'll take a closer look and see if I can spot where the problem is.

I suppose trig substitution could be applied to any integral, but where it's most commonly used is where you have the square root of a sum or difference of squares. The radical can appear in the numerator, but commonly appears in the denominator.

The idea with trig substitution is to apply the substitution to get an integral that you can actually evaluate, so I don't see it used with cube roots, or the like, or with simple polynomials or power functions, as in your example.

LaTeX isn't hard to use. Here's the LaTeX for the integral you started with. To make it actually render, put a pair of $ signs at the beginning, and another pair at the end.

\int \sqrt{9 + 16x^2}dx

Edit: Dick beat me to it, so I won't take a closer look.
Yeah, I can see where it's convenient to use, I was just wondering if there were any inputs in which θ would lead to an undefined expression where, in the original expression written in terms of x, there would be a defined answer.

However, I worked it out for a specific example on paper and saw that when θ gave undefined values, the corresponding x for that θ would have given undefined values anyways. Sorry if my wording was a little strange, but I'm satisfied now. It had been bothering me for a couple of days.
Dick
#5
Jul31-12, 10:01 PM
Sci Advisor
HW Helper
Thanks
P: 25,251
It should all work out ok. If you take your original example of integrating 1/x by substituting x=tan(t) you should wind up with log(|tan(t)|). Sure that has problems all over the place, but when you change back to x you get log(|x|) and everything is ok again. Glad you are feeling better about it.


Register to reply

Related Discussions
Integral involving trig substitution Calculus & Beyond Homework 2
Integrals involving trig substitution Calculus & Beyond Homework 3
Integration involving Substitution Calculus & Beyond Homework 3
Integration by trig substitution Calculus & Beyond Homework 3
Integration using Trig Substitution Calculus & Beyond Homework 9