## Simplification Problem before Finding Derivative

1. The problem statement, all variables and given/known data

I have a bit of confusion surrounding one of my basic derivative problems:

Find the derivative of the following:

f(x) = \frac{x - 3x{\sqrt{x}}}{\sqrt{x}}

2. Relevant equations

None, I believe.

3. The attempt at a solution

I think I can simplify this, so I separate them:

\frac{x}{x^{1/2}} - \frac{3x. x^{1/2}}{x^{1/2}}

Using the indices laws, I add and subtract:

x^{-1/2} - 3x

Now it's simplified as far as I can see, so I take the derivative:

\frac{-1}{2}x^{-3/2} - 3

\frac{-1}{2\sqrt{x^3}} - 3

I'm confused about simplifying the exponents the way I did. If I have to use the quotient law, I'm not too sure how to apply it correctly in this case.

Recognitions:
Homework Help
 Quote by johnstobbart 1. The problem statement, all variables and given/known data I have a bit of confusion surrounding one of my basic derivative problems: Find the derivative of the following: f(x) = \frac{x - 3x{\sqrt{x}}}{\sqrt{x}} 2. Relevant equations None, I believe. 3. The attempt at a solution I think I can simplify this, so I separate them: \frac{x}{x^{1/2}} - \frac{3x. x^{1/2}}{x^{1/2}} Using the indices laws, I add and subtract: x^{-1/2} - 3x Now it's simplified as far as I can see, so I take the derivative: \frac{-1}{2}x^{-3/2} - 3 And my final answer is: \frac{-1}{2\sqrt{x^3}} - 3 I'm confused about simplifying the exponents the way I did. If I have to use the quotient law, I'm not too sure how to apply it correctly in this case.
Why do you claim that $$\frac{x}{\sqrt{x}} = \frac{1}{\sqrt{x}}?$$ The claim is false. If, as you claim, you are just adding/subtracting exponents, then you seem to be saying that 1 - 1/2 = -1/2.

RGV

 Quote by Ray Vickson Why do you claim that $$\frac{x}{\sqrt{x}} = \frac{1}{\sqrt{x}}?$$ The claim is false. If, as you claim, you are just adding/subtracting exponents, then you seem to be saying that 1 - 1/2 = -1/2. RGV
Sorry. I made an error. Let me try fix it.
When I simplify f(x) (hopefully correctly this time), I get:

x^{1/2} - 3x

Then when taking the derivative, I get:

\frac{x^{-1/2}}{2} - 3

\frac{1}{2\sqrt{x}} - 3

## Simplification Problem before Finding Derivative

$$\frac{d}{dx}\frac{x-3x^{3/2}}{x^{1/2}}$$
$$\frac{d}{dx}x^{1/2}-3\frac{d}{dx}x$$
$$\int \frac{1}{2\sqrt{x}}-3\,dx=\frac{1}{2}\int x^{-1/2}\,dx - 3x=\sqrt{x}-3x$$