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Simplification Problem before Finding Derivative |
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| Aug8-12, 11:32 AM | #1 |
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Simplification Problem before Finding Derivative
1. The problem statement, all variables and given/known data
I have a bit of confusion surrounding one of my basic derivative problems: Find the derivative of the following: \begin{equation} f(x) = \frac{x - 3x{\sqrt{x}}}{\sqrt{x}} \end{equation} 2. Relevant equations None, I believe. 3. The attempt at a solution I think I can simplify this, so I separate them: \begin{equation} \frac{x}{x^{1/2}} - \frac{3x. x^{1/2}}{x^{1/2}} \end{equation} Using the indices laws, I add and subtract: \begin{equation} x^{-1/2} - 3x \end{equation} Now it's simplified as far as I can see, so I take the derivative: \begin{equation} \frac{-1}{2}x^{-3/2} - 3 \end{equation} And my final answer is: \begin{equation} \frac{-1}{2\sqrt{x^3}} - 3 \end{equation} I'm confused about simplifying the exponents the way I did. If I have to use the quotient law, I'm not too sure how to apply it correctly in this case. |
| Aug8-12, 11:49 AM | #2 |
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Recognitions:
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RGV |
| Aug8-12, 12:24 PM | #3 |
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When I simplify f(x) (hopefully correctly this time), I get: \begin{equation} x^{1/2} - 3x \end{equation} Then when taking the derivative, I get: \begin{equation} \frac{x^{-1/2}}{2} - 3 \end{equation} My final answer is: \begin{equation} \frac{1}{2\sqrt{x}} - 3 \end{equation} |
| Aug8-12, 01:48 PM | #4 |
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Simplification Problem before Finding Derivative
Writing your problem in terms of exponents instead of radicals make it easier:
[tex]\frac{d}{dx}\frac{x-3x^{3/2}}{x^{1/2}}[/tex] Split that up to get [tex]\frac{d}{dx}x^{1/2}-3\frac{d}{dx}x[/tex] Then your answer is correct. To check your work, it is always good to integrate what you got: [tex]\int \frac{1}{2\sqrt{x}}-3\,dx=\frac{1}{2}\int x^{-1/2}\,dx - 3x=\sqrt{x}-3x[/tex] which is what we started with. |
| Aug8-12, 02:35 PM | #5 |
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I haven't started on integration yet, but I do know I'll be doing it soon. Thanks a lot for all your patience and time Millenial and Ray Vickson.
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