Linear Transformation question

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SUMMARY

This discussion focuses on identifying linear transformations, specifically projections, reflections, and rotations, using matrix representations. The transformation T[x y] = 1/2[x - y, y - x] is analyzed, leading to the matrix [1 -1; -1 1], which is determined to be a reflection due to its properties. Another transformation, represented by the matrix [1/2, √3/2; √3/2, 1/2], is discussed as a potential rotation, but it is clarified that for a matrix to represent a rotation, it must be orthogonal with a determinant of 1.

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matrix_204
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i was trying to figure out something that i didn't understand and the book doesn't have much examples of it either. My question is how do u know whether a transformation is a projection on a line, reflection on a line, or rotation through an angel? With T given. The questions i did from the book, i was able to find the line and reflection, since the same question was previously stated and i was able to do it, n got the answer from there, but didn't understand it.
Take T[x y]=1/2[x-y y-x] and by solving these i get [1 -1]/[-1 1] (this is not division, just goes at the bottom, its a 2x2 matrix, and the vectors r transposed) so by looking at this
[ 1 -1]
[-1 1]
how can u tell whether its a reflection, projection or rotation?
Similarly another result i got for another part was
[1/2 root3/2]
[root3/2 1/2 ]
i think this one is rotation but how can u tell?
 
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A rotation about the origin is a transformation which preserves the lengths and angles of vectors. It's called an orthogonal transformation. They are given by an orthogonal matrix, possesing the following property:
[tex]A^TA=I[/tex]
where the T denotes the transpose operation.
Furthermore: if det(A)=1, then it's a rotation, if det(A)=-1, then it's a reflection followed by a rotation.
Also, a rotation over an angle [itex]\theta[/itex] can always be given by the following matrix:

[tex]\left( \begin{array}{cc}\cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{array} \right)[/tex]
Since [itex]\cos \frac{\pi}{3}=1/2[/itex] and [itex]\sin \frac{\pi}{3} = \frac{\sqrt{3}}{2}[/itex] the matrix:
[tex]\left( \begin{array}{cc}1/2 & -\frac{\sqrt{3}}{2} \\ \frac{\sqrt{3}}{2} & 1/2 \end{array} \right)[/tex]
is matrix for the rotation about an angle of [itex]\pi/3[/itex]. (Did you forgot a minus sign in your matrix?)

Projections always have the following properties:
[tex]P^T=P[/tex]
[tex]P^2=P[/tex].
 
matrix_204 said:
Take T[x y]=1/2[x-y y-x] and by solving these i get [1 -1]/[-1 1] (this is not division, just goes at the bottom, its a 2x2 matrix, and the vectors r transposed) so by looking at this
[ 1 -1]
[-1 1]

You have omitted 1/2.

[tex]T=1/2 \left(\begin {array}{cc} 1&-1\\ -1& 1\end{array}\right)[/tex]

how can u tell whether its a reflection, projection or rotation?

Find out what does this transformation do with the base vectors. You will see that they are projected onto the [1,-1] direction.

Similarly another result i got for another part was
[1/2 root3/2]
[root3/2 1/2 ]
i think this one is rotation but how can u tell?

To be a rotation, the matrix should be unitary, and yours is not (the determinant should be 1).
A matrix that represents an anti-clockwise rotation by angle alpha in the (xy) plane is

[tex]T=\left(\begin {array}{cc}\cos(\alpha)&-\sin(\alpha)\\ \sin(\alpha)&\cos(\alpha)\end{array}\right )[/tex]

ehild
 

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