Learn How to Solve sin(nx)/n for Infinity with Expert Guidance"

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Discussion Overview

The discussion revolves around the summation of the series involving sin(nx)/n as n approaches infinity. Participants are exploring methods to derive the result of this series, particularly in relation to specific intervals of x. The scope includes mathematical reasoning and potential applications in Fourier analysis.

Discussion Character

  • Exploratory, Mathematical reasoning

Main Points Raised

  • One participant presents the series sum of sin(nx)/n and suggests that the result should be (1/2)*(pi-x) for 0 < x < pi and -(1/2)*(pi+x) for -pi < x < 0.
  • Another participant proposes expressing sin(nx)/n as the imaginary part of e^(inx)/n, hinting at the use of logarithmic series.
  • A correction is made regarding the identification of sin as the imaginary part and cos as the real part, indicating a potential misunderstanding in the previous posts.
  • One participant suggests computing the Fourier coefficients of x as a possible approach to tackle the problem.
  • A subsequent correction reiterates the distinction between the imaginary and real parts of the sine and cosine functions.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the approach to solving the problem, with multiple competing views and methods being proposed.

Contextual Notes

There are indications of missing assumptions regarding the convergence of the series and the definitions of the functions involved. The discussion also reflects unresolved mathematical steps related to the proposed methods.

Who May Find This Useful

Readers interested in series summation, Fourier analysis, and mathematical problem-solving may find this discussion relevant.

Bossieman
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sum (sin(nx)/n)
where n goes from 1 to infinity.
The result should be (1/2)*(pi-x) when 0(x(pi
and -(1/2)*(pi+x) when -pi(x(0

I need someone to show me how to attack this problem.
Thanks
 
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sin(nx)/n = RE[e^inx/n]
(Further Hint : log series)

-- AI
 
Correction to TenaliRaman. sin is imaginary part, cos is real part.
 
I would try computing the Fourier coefficents of x.
 
mathman said:
Correction to TenaliRaman. sin is imaginary part, cos is real part.
OOPS!

-- AI
 

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