Force Experienced by an Electron in an Electric Field

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SUMMARY

An electron placed in an electric field of strength 300 N/C experiences a force calculated using the formula F = qE, where q is the charge of the electron (1.6 x 10^-19 C). The correct force is 4.8 x 10^-17 N, which is not among the provided options. For a particle with a mass of 0.005 kg and a charge of +4.0 µC in an electric field opposing gravity, the field strength required to balance the weight is calculated using E = mg/q, yielding a value of 1.225 x 10^4 N/C, which also does not match the given choices. The discussion highlights the importance of correctly applying fundamental physics equations to solve problems.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with the equation F = qE
  • Knowledge of mass, weight, and gravitational force
  • Basic proficiency in unit conversions (e.g., microcoulombs to coulombs)
NEXT STEPS
  • Review the principles of electrostatics and electric fields
  • Study the derivation and application of the equation F = qE
  • Learn about balancing forces in electric fields and gravitational fields
  • Explore unit conversions and their importance in physics calculations
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Students studying physics, educators teaching electrostatics, and anyone interested in understanding the interaction between electric fields and charged particles.

Soaring Crane
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An electron is placed in an electric field of strength 300 N/C. What is the magnitude of the force the electron experiences?
1.6x10^13 N
2.4x10^13 N
3.2x10^14 N
4.8x10^14 N
6.4x10^14 N

A particle of mass 0.005 kg is given a charge of +4.0 µC and is placed in an electrical field that is directed antiparallel to the Earth's gravitational field. What is the field strength, expressed in N/C, if it balances the weight of the particle?
1.6 x10^6
2.4 x10^6
3.2 x10^6
4.4 x10^6
4.7 x10^6

Wen I tried to do these questions, I did not even come close to the figure in bold. I thought F = Eq or F = mg/q would be sufficient enough, but I guess not. Can anyone explain how to arrive at each answer?

Thanks.
 
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F = Eq is the correct equation to use for the first part, but all those answers listed are wrong.
q is the charge of an electron = 1.6 * 10^-19 C,
Just look at the exponents. You would have to have an E in the order of 10^33 N/C in order to come anywhere near those numbers. Are you sure you copied the question correctly?

For the second, I think you mean E = mg/q not F = mg/q. Again, all the choices are wrong? Where did you get these questions?
 
Soaring Crane said:
An electron is placed in an electric field of strength 300 N/C. What is the magnitude of the force the electron experiences?
1.6x10^13 N
2.4x10^13 N
3.2x10^14 N
4.8x10^14 N
6.4x10^14 N
None of these answers are even close to being right. The force is qE. If E is 300 and q is 1.6e-19 Coulomb, qE = 4.8e-17 N.

A particle of mass 0.005 kg is given a charge of +4.0 µC and is placed in an electrical field that is directed antiparallel to the Earth's gravitational field. What is the field strength, expressed in N/C, if it balances the weight of the particle?
1.6 x10^6
2.4 x10^6
3.2 x10^6
4.4 x10^6
4.7 x10^6
Again: F = qE, but in this case F also = mg, so qE = mg; E = mg/q

Plugging in the numbers, E = 5e-3*9.8/4e-6 = 1.225 e4 N/C Again none of the answers fit.

Where did you get these questions?

AM
 

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